**Calculate the Escape Velocity of Titan**In the study of celestial mechanics, the escape velocity is the speed at which an object must travel to break free from the gravitational pull of a celestial body without further propulsion. To calculate the escape velocity of Titan, Saturn's largest moon, you can use the formula:\[ v = \sqrt{\frac{2GM}{r}} \]Where:- \( v \) is the escape velocity.- \( G \) is the gravitational constant (\(6.67430 \times 10^{-11} \, \text{m}^3 \text{kg}^{-1} \text{s}^{-2}\)).- \( M \) is the mass of Titan.- \( r \) is the radius of Titan.The specific values for Titan's mass and radius are:- Mass (\( M \)): \( 1.3452 \times 10^{23} \, \text{kg} \)- Radius (\( r \)): \( 2,575,000 \, \text{m} \)Plugging these values into the formula will yield the escape velocity for Titan.

All objects with mass will have a force of attraction between them which depends on the mass of the…

Answered: Calculate the escape velocity of Titan.

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In January 2005, the Huygens probe landed on Saturn's moon Titan, the only satellite in the solar system having a thick atmosphere Titan's diameter is 5150 km, and its mass is 1,35 x 10* kg. The probe welghed 2120 N on the earth.