Calculate the equilibrium constant for the following reaction at 37 °C. AGO-3.13 kJ/mol Fumarate + H2O → Malate Type your answer...

How is the pH scale defined? What range of pH values corresponds to acidic solutions? What range corresponds to basic solutions? Why is pH = 7.00 considered neutral? When the pH of a solution changes by one unit, by what factor does the hydrogen ion concentration change in the solution? How is pOH defined? How arc pH and pOH for a given solution related? Explain.

Obtain the equilibrium constant for the reaction HCN(aq)H+(aq)+CN(aq) from the following HCN(aq)+OH(aq)CN(aq)+H2O(l);K1=4.9104H2O(l)H+(aq)+OH(aq);K2=1.01014

Given that the Gf for Pb2+(aq) and Cl-(aq) is -24.3 kJ/mole and -131.2 kJ/mole respectively, determine the solubility product, Ksp, for PbCl2(s).

Calculate K for the reactions in Question 1.

Write the balanced chemical reaction for this equilibrium expression: K= [H2O]P[O2] [H2O2]?

#9 part E

Suppose a pair of chemical compounds A andB can react in two different ways: A+BC Reaction 1 gives product C. A+BD Reaction 2 gives product D. The following facts are known about the two reactions: • Reaction 1 is endothermic and Reaction 2 is exothermic. • If a reaction vessel is charged (illed") with A and B, then at first Cis produced faster than D. Use these facts to sketch a qualitative reaction energy diagram for both reactions. Note: because these sketches are only qualitative, the energies don't have to be exact. They only have to have the right relationship to each other. For example, if one energy is less than another, that fact should be clear in your sketch. Reaction 1 Reaction 2 energy energy reaction coordinate reaction coordinate

Question 8 of 10 Balance the following chemical equation (if necessary): co() PBCO(s) → PbO(s) + D4+ 4 6 8 9 Os Os O, D. + (s) (1) (g) (aq) Pbo Co. PbCO, Reset •x H:O Delete

Considering the reaction and the information in the Excel table below, what should be entered into cell D3 to calculate Kc?     A B C D 1 Equilibrium Concentration (M)   2 Fe3+ SCN- Fe(SCN)2+ Equilibrium Constant 3 9.70E-04 1.70E-04 2.60E-05             =C3/(A3*B3^2)     =C3/(A3^2*B3)     =C3/(A3*B3)^2     =A3*B3^2/C3     =C3/(A3*B3)