Calculate the equilibrium concentration of Ni²* in a solution with an analytical NİY2- concentration of 0.0100 M at pH 2.0 and pH 9.0. K; of NIY2= 4.2 x 1018
Calculate the equilibrium concentration of Ni²* in a solution with an analytical NİY2- concentration of 0.0100 M at pH 2.0 and pH 9.0. K; of NIY2= 4.2 x 1018
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![Calculate the equilibrium concentration of Ni²* in a solution with an analytical NİY2-
concentration of 0.0100 M at pH 2.0 and pH 9.0.
Kr of NIY2= 4.2 x 1018
HẠY Dissociation Constants:
Ka1 =1.02 x 10² Ka2 =2.14 x 103
Ka3 =6.92 x 10-7 Ka4 =5.50 x 10-11](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb6b99199-f777-4e10-8574-c308dd089ab2%2Fabec340d-9c64-4891-bc1e-da28197131fc%2Fsm12a5v_processed.png&w=3840&q=75)
Transcribed Image Text:Calculate the equilibrium concentration of Ni²* in a solution with an analytical NİY2-
concentration of 0.0100 M at pH 2.0 and pH 9.0.
Kr of NIY2= 4.2 x 1018
HẠY Dissociation Constants:
Ka1 =1.02 x 10² Ka2 =2.14 x 103
Ka3 =6.92 x 10-7 Ka4 =5.50 x 10-11
![For METAL COMPLEX EQUILIBRIA # 2, use the following values:
Zn(NH3)n2*: pKm, = 2.21, 2.29, 2.36, 2.03
ZnY2: K = 3.0 x 1016
EDTA: Ka1 = 1.02 x 102, Ka2 = 2.14 x 103, Ka3 = 6.92 x 107, Ka4 = 5.50 x 1011
%3D
%3D](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb6b99199-f777-4e10-8574-c308dd089ab2%2Fabec340d-9c64-4891-bc1e-da28197131fc%2F1htcrnr_processed.png&w=3840&q=75)
Transcribed Image Text:For METAL COMPLEX EQUILIBRIA # 2, use the following values:
Zn(NH3)n2*: pKm, = 2.21, 2.29, 2.36, 2.03
ZnY2: K = 3.0 x 1016
EDTA: Ka1 = 1.02 x 102, Ka2 = 2.14 x 103, Ka3 = 6.92 x 107, Ka4 = 5.50 x 1011
%3D
%3D
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