Calculate the equation of the circle which is centered at the point of intersection of the lines x+3y+3=0 and x+y+1=0 and its radius is equal to 5

Q: ind the equation of the circle with radius 5 whose center lies on the x-axis and passes  through the…

A: Since the radius of the circle is 5 and its center lies on the x-axis,the equation of the circleis…

Q: Consider the equation of the circle given as: 3x^2 + 3y^2 + 6x - 4y=0.The corresponding center of…

A: The center radius of the circle is given by  (x-h)2+(y-k)2=r2 where center is (h,k)r is the radius…

Q: The center of the circle (x+3)2+(y-2)2=13 is(3,-2)

A: The given circle equation is (x+3)2+(y-2)2=13

Q: What is the equation of the circle passing through the points A(-1,3) and B(3,-3) and whose center…

A:

Q: find the equation of the circle through (-2, 1) (4,-3) and (4,7)

A: Given, (-2,1),(4,-3) and (4,7)