Calculate the entropy changes of the system and surrounding for the case of isothermal freezing of one mole of supercooled liquid silver at 804°C, when the surrounding are also at the same temperature. sys. = sur. = Given: Melting point of silver = 961°C Heat of fusion of silver at 961°C = 11255 J/mol Cp Ag(s) = 21.30+ 8.54x10-³xT cal/deg/mole Cp. Ag(1) = 30.54 J/K/mol

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Calculate the entropy changes of the system and surrounding for the case of isothermal freezing of one mole of supercooled liquid silver at 804°C, when the surrounding are also at the same temperature.

Calculate the entropy changes of the system and surrounding for the case of isothermal freezing of one mole of supercooled liquid silver at 804°C, when the surrounding are also at the same temperature.
Ssys.
Ssur. =
=
Given: Melting point of silver = 961°C
Heat of fusion of silver at 961°C = 11255 J/mol
Cp, Ag(s) = 21.30 +8.54×10-³×T cal/deg/mole
Cp. Ag(1) = 30.54 J/K/mol
Transcribed Image Text:Calculate the entropy changes of the system and surrounding for the case of isothermal freezing of one mole of supercooled liquid silver at 804°C, when the surrounding are also at the same temperature. Ssys. Ssur. = = Given: Melting point of silver = 961°C Heat of fusion of silver at 961°C = 11255 J/mol Cp, Ag(s) = 21.30 +8.54×10-³×T cal/deg/mole Cp. Ag(1) = 30.54 J/K/mol
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