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Calculate the entropy change ΔS and comment on the sign of the change. NH4Cl(s) → NH4Cl (aq) Values of 298 K : NH4Cl(s) - ΔH (kJ/mol) = - 314.43  ΔS (J/Kmol) = 94.6 NH4Cl (aq) - ΔH (kJ/mol) = - 299.66  ΔS (J/Kmol) = 169.9

Calculate the entropy change ΔS and comment on the sign of the change. NH4Cl(s) → NH4Cl (aq) Values of 298 K : NH4Cl(s) - ΔH (kJ/mol) = - 314.43  ΔS (J/Kmol) = 94.6 NH4Cl (aq) - ΔH (kJ/mol) = - 299.66  ΔS (J/Kmol) = 169.9

Chemistry: Principles and Practice
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter17: Chemcial Thermodynamics
Section: Chapter Questions
Problem 17.52QE
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Calculate the entropy change ΔS and comment on the sign of the change. NH4Cl(s) → NH4Cl (aq)

Values of 298 K :

NH4Cl(s) - ΔH (kJ/mol) = - 314.43  ΔS (J/Kmol) = 94.6

NH4Cl (aq) - ΔH (kJ/mol) = - 299.66  ΔS (J/Kmol) = 169.9

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