Calculate the entropy change ΔS and comment on the sign of the change. NH4Cl(s) → NH4Cl (aq) Values of 298 K : NH4Cl(s) - ΔH (kJ/mol) = - 314.43 ΔS (J/Kmol) = 94.6 NH4Cl (aq) - ΔH (kJ/mol) = - 299.66 ΔS (J/Kmol) = 169.9
Calculate the entropy change ΔS and comment on the sign of the change. NH4Cl(s) → NH4Cl (aq) Values of 298 K : NH4Cl(s) - ΔH (kJ/mol) = - 314.43 ΔS (J/Kmol) = 94.6 NH4Cl (aq) - ΔH (kJ/mol) = - 299.66 ΔS (J/Kmol) = 169.9
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter16: Thermodynamics: Directionality Of Chemical Reactions
Section: Chapter Questions
Problem 27QRT
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Question
Calculate the entropy change ΔS and comment on the sign of the change. NH4Cl(s) → NH4Cl (aq)
Values of 298 K :
NH4Cl(s) - ΔH (kJ/mol) = - 314.43 ΔS (J/Kmol) = 94.6
NH4Cl (aq) - ΔH (kJ/mol) = - 299.66 ΔS (J/Kmol) = 169.9
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