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Calculate the enthalpy of the following reaction: HCI + NaOH Nacl + H,0 AH HCI- -92.3 kJ/mol NAOH= -426.7 kJ/mol NaCl= -411 kJ/mol H20= -286 kl/mol Reaction: ΔΗ+ kJ/mol

Calculate the enthalpy of the following reaction: HCI + NaOH Nacl + H,0 AH HCI- -92.3 kJ/mol NAOH= -426.7 kJ/mol NaCl= -411 kJ/mol H20= -286 kl/mol Reaction: ΔΗ+ kJ/mol

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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arents Resou X 8 Thermochemistry Calculations | S x illeenisd.schoology.com/assignment/4885571303/assessment O f fb a Amazon Smile y Twitter Free Invoice Genera.. I banx 3 DG Login nd My Device mail Question 3 (1 point) Calculate the enthalpy of the following reaction: HCI + NAOH Nacl + H,0 ΔΗ HCl= -92.3 kJ/mol NaOH= -426.7 kj/mol Nacl= -411 k/mol H20= -286 kJ/mol Reaction: ΔΗ kJ/mol Blank 1: Question 4 (1 point) Calculate the energy change when 25.0 g of magnesium changes from from 27°C to 45°C. The specific heat of magnesium is Blank 1: Type here to search 78 no
Transcribed Image Text:arents Resou X 8 Thermochemistry Calculations | S x illeenisd.schoology.com/assignment/4885571303/assessment O f fb a Amazon Smile y Twitter Free Invoice Genera.. I banx 3 DG Login nd My Device mail Question 3 (1 point) Calculate the enthalpy of the following reaction: HCI + NAOH Nacl + H,0 ΔΗ HCl= -92.3 kJ/mol NaOH= -426.7 kj/mol Nacl= -411 k/mol H20= -286 kJ/mol Reaction: ΔΗ kJ/mol Blank 1: Question 4 (1 point) Calculate the energy change when 25.0 g of magnesium changes from from 27°C to 45°C. The specific heat of magnesium is Blank 1: Type here to search 78 no
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