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Calculate the enthalpy of formation of PCL5 (s), given the heats of the following reactions at 25C: 2P (s) + 3 C12 = 2PCI3 (1) H = - 635.13 KJ/mol PCI3 (1) + 2 C12 = PCI5 (s) H = - 137.28 KJ/mol Select the correct response: -772.41 KJ/mol -497.85 KJ/mol O -386 2K /mol

Calculate the enthalpy of formation of PCL5 (s), given the heats of the following reactions at 25C: 2P (s) + 3 C12 = 2PCI3 (1) H = - 635.13 KJ/mol PCI3 (1) + 2 C12 = PCI5 (s) H = - 137.28 KJ/mol Select the correct response: -772.41 KJ/mol -497.85 KJ/mol O -386 2K /mol

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Table 6.3 Standard Enthalpies of Formation of Some Inorganic Substances at 25°C Substance AH; (kJ/mol) Substance AH? (kJ/mol) - 187.6 Ag(s) AgCl(s) H,O2(/) - 127.04 Hg(/) Al(s) 2(s) Al,03(s) - 1669.8 HI(g) 25.94 Br2() Mg(s) HBr(g) C(graphite) -36.2 MgO(s) -601.8 M9CO (s) N2(g) NH3(g) NO(g) NO2(g) N204(g) -1112.9 C(diamond) 1.90 CO(g) Co,(G) Ca(s) -110.5 -46.3 -393.5 90.4 33.85 CaO(s) -635.6 9.66 CaCO3(s) -1206.9 N20(g) 81.56 O(g) 249.4 HCIG) O2(g) O3(g) -92.3 Cu(s) 142.2 CuO(s) -155.2 S(rhombic) S(monoclinic) SO-(g) SO;(g) F2(g) 0.30 HF(g) H(g) -268.61 -296.1 218.2 -395.2 H2(g) H,S(g) -20.15 H2O(g) -241.8 ZnO(s) -347.98 H20(1) -285.8
Transcribed Image Text:Table 6.3 Standard Enthalpies of Formation of Some Inorganic Substances at 25°C Substance AH; (kJ/mol) Substance AH? (kJ/mol) - 187.6 Ag(s) AgCl(s) H,O2(/) - 127.04 Hg(/) Al(s) 2(s) Al,03(s) - 1669.8 HI(g) 25.94 Br2() Mg(s) HBr(g) C(graphite) -36.2 MgO(s) -601.8 M9CO (s) N2(g) NH3(g) NO(g) NO2(g) N204(g) -1112.9 C(diamond) 1.90 CO(g) Co,(G) Ca(s) -110.5 -46.3 -393.5 90.4 33.85 CaO(s) -635.6 9.66 CaCO3(s) -1206.9 N20(g) 81.56 O(g) 249.4 HCIG) O2(g) O3(g) -92.3 Cu(s) 142.2 CuO(s) -155.2 S(rhombic) S(monoclinic) SO-(g) SO;(g) F2(g) 0.30 HF(g) H(g) -268.61 -296.1 218.2 -395.2 H2(g) H,S(g) -20.15 H2O(g) -241.8 ZnO(s) -347.98 H20(1) -285.8
Question 6 of 10 Calculate the enthalpy of formation of PCL5 (s), given the heats of the following reactions at 25C: 2P (s) + 3 C12 = 2PC13 (I) H = - 635.13 KJ/mol PCI3 (1) + 2 C12 = PCI5 (s) H = - 137.28 KJ/mol Select the correct response: -772.41 KJ/mol -497.85 KJ/mol -386.2 KJ/mol -248.92 KJ/mol
Transcribed Image Text:Question 6 of 10 Calculate the enthalpy of formation of PCL5 (s), given the heats of the following reactions at 25C: 2P (s) + 3 C12 = 2PC13 (I) H = - 635.13 KJ/mol PCI3 (1) + 2 C12 = PCI5 (s) H = - 137.28 KJ/mol Select the correct response: -772.41 KJ/mol -497.85 KJ/mol -386.2 KJ/mol -248.92 KJ/mol
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