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Calculate the Enthalpy of change in Kj/mol and % difference in the neutralization reaction below:   HNO2 + NH3 = N2 + 2 H2O   Initial Temp= 20 Deg celsius   Final Temp= 22.3 Deg celsius   Conc= 0.4 M [HNO3] and 0.4 M [NH3]   Vol= 55 mL [HNO2] and 60 mL [NH3]= Mass is 115 g   Specific Heat= 4.184 J/g   For the other value in % difference use: -348

Calculate the Enthalpy of change in Kj/mol and % difference in the neutralization reaction below:   HNO2 + NH3 = N2 + 2 H2O   Initial Temp= 20 Deg celsius   Final Temp= 22.3 Deg celsius   Conc= 0.4 M [HNO3] and 0.4 M [NH3]   Vol= 55 mL [HNO2] and 60 mL [NH3]= Mass is 115 g   Specific Heat= 4.184 J/g   For the other value in % difference use: -348

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Calculate the Enthalpy of change in Kj/mol and % difference in the neutralization reaction below:

 

HNO2 + NH3 = N2 + 2 H2O

 

Initial Temp= 20 Deg celsius

 

Final Temp= 22.3 Deg celsius

 

Conc= 0.4 M [HNO3] and 0.4 M [NH3]

 

Vol= 55 mL [HNO2] and 60 mL [NH3]= Mass is 115 g

 

Specific Heat= 4.184 J/g

 

For the other value in % difference use: -348

Kj/mol

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