Calculate the enthalpy change when 5 L of liquid NH3 is burned in air to give N3 (9) and H3O(g). Express your answer using two significant figures. AH° - -7.0x10 kJ Subm Previous Answers v Correct Part B How does this compare with AH tor the complete combustion of 1 L of liquid methanol, CH,OH(1)? For CH,OH(1), the density at 25 °C is 0.792 g/cm, and AH; equals -239 kJ/mol. Essay answers are limited to about 500 words (3800 characters maximum, including spaces). 3800 Character(s) remaining Request Answer Submit purse Home Ammonia (NH3) boils at -33° C; at this temperature it has a density of 0.81 g/cm. The enthalpy of formation of NH3 (g) is -46.2 kJ/mol, and the enthalpy of vaporization of NH3 (1) is 23.2 kJ/mol.

Calculate the enthalpy change when 5 L of liquid NH3 is burned in air to give N3 (9) and H3O(g). Express your answer using two significant figures. AH° - -7.0x10 kJ Subm Previous Answers v Correct Part B How does this compare with AH tor the complete combustion of 1 L of liquid methanol, CH,OH(1)? For CH,OH(1), the density at 25 °C is 0.792 g/cm, and AH; equals -239 kJ/mol. Essay answers are limited to about 500 words (3800 characters maximum, including spaces). 3800 Character(s) remaining Request Answer Submit purse Home Ammonia (NH3) boils at -33° C; at this temperature it has a density of 0.81 g/cm. The enthalpy of formation of NH3 (g) is -46.2 kJ/mol, and the enthalpy of vaporization of NH3 (1) is 23.2 kJ/mol.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

The following table is the data a student recorded after completing the Hess' Law Lab (VCL 3-12). 200.0 ml of water was added the measured amount of solid NaOH in a calorimeter. Parameter Reaction 1 Mass NaOH (g) 4.575 25.00 Initial temperature (°C) 30.05 Final temperature (°C) Using all the steps and procedues of this lab, calculate the energy released (kJ/mol) of NaOH in Reaction 1.
When 0.576 g of biphenyl (C12H10) undergoes combustion in a bomb calorimeter, the temperature rises from 26.2 °C to 30.4 °C. Find AErxn for the combustion of biphenyl. The heat capacity of the bomb calorimeter, determined in a separate experiment, is 5.86 kJ/°C. Express the energy in kilojoules per mole to three significant figures. > View Available Hint(s) ? AExn = kJ/mol
+Tools - 4 of 7 - + & 8C 11. When 0.10 moles of butane, CAH10, are combusted in a bomb calorimeter, the temperature of the system increases by 8.5°C. If the system has a heat capacity of 34 kJ/°C, what is the heat of combustion of butane in kJ/mol CaH10? Que Bomb Calorimeter Thermometer Water Bomb Reaction A AHcomb = -290 kJ/mol C4H10 B AHcomb = -2900 kJ/mol CaH10 Question C AHcomb = 290 kJ/mol CaH10 O A D AHcomb = 2900 k)/mol CAH10 Activate Go to Settin C2021lluminate EducationT Inc. e DELL F6 a F7 F8 F9 F12 Insert FS F10 Esc F11 PriScr F1 F2 F3 F4 %23 %24 13 4 10 Tab E R OP Lock S K C Alt Alt つ
5. Acetylene (C₂H₂) can react with water to produce acetaldehyde (C₂H4O) as shown below. Calculate AH of acetylene using the equation and the table provided. C₂H₂(g) + H₂O (g) → C₂H.O(g) AH Compound AH? (kJ/mol) H₂O(g) C₂H₂O(g) a. -257 kJ/mol b. 257 kJ/mol -242 -166 = -151 kJ ran c. -227 kJ/mol d. 227 kJ/mol
Imagine an endothermic reaction had been studied (i.e. AHºrn > 0). In this experiment we assumed the calorimeter was perfect (Acalorimeter = 0). If, however, the calorimeter were not perfect and heat flowed from the calorimeter to the contents, would the measured AH Txn be more or less endothermic than the true AH°? rxn
2. Circle the best answer, of the italicized words, when considering the following reaction: 2 HNO3(aq) + NO(g) → 3 NO2(g) + H20(1) AH°rxn = +137 kJ a. Is this reaction exothermic or endothermic? b. If NO gas is bubbled into a flask containing aqueous HNO3 , will the temperature of the water in the flask increase or decrease? C. Are the reactants at a higher or lower energy than the products?
A chemist measures the enthalpy change AH during the following reaction: P4(s) + 6 Cl₂(g) →4 PC13(g) AH-1148. kJ Use this information to complete the table below. Round each of your answers to the nearest kJ/mol. reaction 20PC1₂ (g) 5P (s) + 30C1₂ (g) 4P (s) + 24C1₂ (g) 4 16PC1₂ (g) 4PC1₂(g) → P4 (s) P₁ (s) + 6C1₂ (8) ΔΗ ៣ kJ KJ ☐ kJ x10 Ś
Sodium chloride added to water (at 25 °C) until it is saturated. Calculate the concentration of sodium ion at this point. AG₁° (kJ/mol) NaCl(s) -384 Na*(aq) -262 Cl(aq) -131 [Na+] = 6.2 M (round answer to 2 sig figs)
cellus_engine.html?ClassID=527350766# 1.00 g of sucrose, C12H22O11, reacts with excess oxygen in a bomb calorimeter with a heat capacity of 12.5 kJ/°C. The initial temperature is 22.0 °C and the final temperature is 23.3 °C. What is the enthalpy of the reaction? AH: [?] kJ/mol Enter either a + or - sign AND the magnitude. Do not round until the end. Use significant figures. AH, rxn (kJ/mol) Enter
Mass of Water Compounds Benzoic Acid + 1000 g Ignite Reset The heat capacity of the calorimeter vessel is 420 J/°C = Calculate A,E (kJ/mol) for the reaction. 1.11 x 10-3 mol sucrose AT 2.14 °C qwater = 5.37 kJ 9cal = 0.898 kJ X kJ/mol FUEGO [Review Topic www
10:11 ull 5G Question 14 of 15 Submit What is the change in enthalpy in kilojoules when 3.24 g of CH;OH gas is completely reacted according to the following reaction? CH;OH(g) → 2 CHa(g) + O2(g) AH = 252.8 kJ X STARTING AMOUNT ADD FACTOR ANSWER RESET *( ) 7.80 x 10-4 2 16.05 mol O2 6.022 x 1023 12.8 J 32.00 0.101 mol CH,OH 1000 3.24 mol CH. 0.001 252.8 g CH,OH 32.05 4.00 x 10-4 g CH. 1 25.6 kJ Tap here or pull up for additional resources
[Review Topics] [Ref Calculate the standard enthalpy change, AH°, for the following reaction at 25°C. Fe2O3 (s) + 2A1(s) → 2Fe(s) + Al, O3 (s) What is the enthalpy change per mole of iron? Substance AH, kJ/mol Fe,O3 (s) -825.5 -1675.7 Standard enthalpy change = kJ Enthalpy change per mole of iron = Submit Answer Retry Entire Group 9 more group attempts remaining LAON tv P.