Calculate the energy required to heat 1.00 kg of graphite from 1.0 °C to 23.3 °C. Assume the specific heat capacity of - 1 graphite under these conditions is 0.710 J-g K'. Round your answer to 3 significant digits.
Calculate the energy required to heat 1.00 kg of graphite from 1.0 °C to 23.3 °C. Assume the specific heat capacity of - 1 graphite under these conditions is 0.710 J-g K'. Round your answer to 3 significant digits.
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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calculate the energy required to heat graphite with the information from the picture
![**Energy Calculation for Heating Graphite**
**Problem Statement:**
Calculate the energy required to heat 1.00 kg of graphite from 1.0 °C to 23.3 °C. Assume the specific heat capacity of graphite under these conditions is 0.710 J·g⁻¹·K⁻¹. Round your answer to 3 significant digits.
**Variables:**
- **Mass (m):** 1.00 kg (1000 g)
- **Initial Temperature (T₁):** 1.0 °C
- **Final Temperature (T₂):** 23.3 °C
- **Specific Heat Capacity (c):** 0.710 J·g⁻¹·K⁻¹
**Approach:**
To find the energy, use the formula:
\[ Q = m \cdot c \cdot \Delta T \]
Where:
- \( Q \) is the heat energy required,
- \( \Delta T = T₂ - T₁ \) is the change in temperature.
**Solution:**
1. Calculate the change in temperature:
\[ \Delta T = 23.3 °C - 1.0 °C = 22.3 °C \]
2. Substitute the values into the formula:
\[ Q = 1000 \, \text{g} \times 0.710 \, \text{J·g⁻¹·K⁻¹} \times 22.3 \, \text{K} \]
3. Compute the result and round to 3 significant digits.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1e77a53e-015e-4d74-8706-0af5e82649c9%2F0f8b3857-5706-4897-a9cd-4096a80e845d%2Ftrwe1sk_processed.png&w=3840&q=75)
Transcribed Image Text:**Energy Calculation for Heating Graphite**
**Problem Statement:**
Calculate the energy required to heat 1.00 kg of graphite from 1.0 °C to 23.3 °C. Assume the specific heat capacity of graphite under these conditions is 0.710 J·g⁻¹·K⁻¹. Round your answer to 3 significant digits.
**Variables:**
- **Mass (m):** 1.00 kg (1000 g)
- **Initial Temperature (T₁):** 1.0 °C
- **Final Temperature (T₂):** 23.3 °C
- **Specific Heat Capacity (c):** 0.710 J·g⁻¹·K⁻¹
**Approach:**
To find the energy, use the formula:
\[ Q = m \cdot c \cdot \Delta T \]
Where:
- \( Q \) is the heat energy required,
- \( \Delta T = T₂ - T₁ \) is the change in temperature.
**Solution:**
1. Calculate the change in temperature:
\[ \Delta T = 23.3 °C - 1.0 °C = 22.3 °C \]
2. Substitute the values into the formula:
\[ Q = 1000 \, \text{g} \times 0.710 \, \text{J·g⁻¹·K⁻¹} \times 22.3 \, \text{K} \]
3. Compute the result and round to 3 significant digits.
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