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Calculate the energy released in the following spontaneous fission reaction: 238U - 95Sr + 140xe + 3n given the atomic masses to be m(U) = 238.050784 u, m(95Sr) = 94.919388 u, m(140xe) = 139.921610 u, and m(n) 238 =1.008665 u.

Calculate the energy released in the following spontaneous fission reaction: 238U - 95Sr + 140xe + 3n given the atomic masses to be m(U) = 238.050784 u, m(95Sr) = 94.919388 u, m(140xe) = 139.921610 u, and m(n) 238 =1.008665 u.

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Calculate the energy released in the following spontaneous fission reaction: 238U - 95Sr + 140xe + 3n given the atomic masses to be m(238U) = 238.050784 u, m(95Sr) = 94.919388 u, m(140xe) = 139.921610 u, and m(n) =1.008665 u.
Transcribed Image Text:Calculate the energy released in the following spontaneous fission reaction: 238U - 95Sr + 140xe + 3n given the atomic masses to be m(238U) = 238.050784 u, m(95Sr) = 94.919388 u, m(140xe) = 139.921610 u, and m(n) =1.008665 u.
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