Answered: Calculate the empirical formula of a…

Calculate the empirical formula of a substance which contains 0.780 g of C, 0.0654 g of H, and 0.693 g of O. O C3H6O2 O CSH3O2 O C3H5O O CgHgO2 C4H6O3 C2H3Q C3H3O2

Introductory Chemistry For Today

8th Edition

ISBN:9781285644561

Author:Seager

Publisher:Seager

Chapter2: Atoms And Molecules

Section: Chapter Questions

Problem 2.32E

See similar textbooks

Related questions

Q: A unknown compound contains only carbon, hydrogen and oxygen. Combustion of 1.00 g this compound…

A: A unknown compound contains only Carbon(C), Hydrogen(H) and Oxygen(O) . Combustion of 1.00 g of this…

Q: A compound contains only carbon, hydrogen, nitrogen, and sulphur. A combustion analyzer collects…

A: Given, A compound contains only carbon hydrogen, nitrogen and sulpur. The combustion analyzer…

Q: 5. If a hydrocarbon compound has a formula mass of 16.04g, what is its empirical formula? О СН2 O…

A: Given :- Empirical formula CH2 CH4 C2H2 CH3 Empirical Formula mass = 16.04 g To identify :-…

Q: An unknown compound contains 57.14% carbon, 6.16% hydrogen, 9.52% nitrogen, and the rest oxygen, by…

Q: Our bodies synthesize protein from amino acids. One of these amino acids is glycine, which has the…

A: First calculate the molecular mass of the compound from given molecular formula.

Q: The empirical formula for xylene is C4H5(l), and its molar mass is 106 g/mol. What is the molecular…

A: Given :- Molar mass of xylene = 106 g/mol Empirical formula = C4H5 To determine :- Its…

Q: 2. The foul odor of rancid butter is due largely to butyric acid, a compound containing carbon,…

A: The foul odour of rancid butter is due largely to butyric acid, a compound containing carbon,…

Q: The empirical formula of a compound is found to be CH5N203. If the molar mass of this compound is…

A: the empirical formula is CH5N2O3

Q: A compound contains only C, H, and N. Combustion of 35.0 mg of the compound produces 54.9 mg CO2 and…

Q: A 5.91 g unknown sample analyzed by elemental analysis revealed a composition of 37.51 % C. In…

A: Given A 5.91 g unknown sample analyzed by elemental analysis revealed a composition of 37.51 % C. In…

Q: Calculate the moles of glucose in 1.0253 g of glucose, C6H12O6. Then calculate the moles of each…

A: Given :- Mass of glucose = 1.0253 g To calculate :- Number of moles of glucose and also determine…

Q: Isopropyl alcohol, sold as rubbing alcohol, is composed of C, H, and O. Combustion of 0.255 g of…

A: 1 mole of CO2 (44 g) contains 1 mole of C (12 g) and two moles of oxygen. The amount of Carbon and…

Q: An experimental technique called elemental analysis reveals that particular antibiotic is composed…

A: From the given data we can easily find the empirical formula of the compound. In the question…

Q: 1. A compound that contains only carbon, hydrogen, and oxygen is 40.54% C and 5.44% H by mass. What…

A: “Since there are multiple questions in this question and it is not mentioned that which one has to…

Q: Give the mass percent of carbon in C14H19NO2 O 38.80% O 2.78% O 5.17% O 71.40%

Q: Suppose you have a compound which has an empirical formula of C4H5N2O and molar mass of 194 g/mol.…

A: We have empirical formula as C4H5N2O We have molar mass as 194 g/mol We have to calculate the…

Q: A 0.4842-g sample of a compound known to contain only carbon, hydrogen, and oxygen was burned in…

A: mass of sample = 0.4842 gmass of CO2 = 0.8635 gmass of H2O = 0.3533 gmolar mass of CO2 = 44.01…

Q: Lycopene (536.88 g/mol) has an empirical formula of C5H7. What is the molecular formula for…

A: The empirical formula mass is calculated as,

Q: Combustion of a 0.66 g sample of a compound containing only carbon, hydro oxygen produced 1.452 g of…

Q: A compound contains only carbon, hydrogen, and oxygen. Combustion of 10.68 mg of the compound yields…

A: The number of moles of the compound can be calculated by dividing the given mass of the compound by…

Q: What is the empirical formula of an unknown compound that contains 48.02% Carbon, 18.74% hydrogen,…

A: The simple number of atoms present in the molecule is shown below.

Q: The empirical formula for Antifreeze is CH,O. What would be the molecular formula if the mass of…

Q: A compound has an empirical formula of HgCl. If the molecular mass of the compound is 472.2 g/mol,…

A: Here we are required to find the molecular formula.

Q: Combustion analysis of 1.200 g of an unknown compound containing carbon, hydrogen, and oxygen…

Q: A 10.68 g sample of compound that contains only carbon, hydrogen, and oxygen was analyzed through…

A: Given mass of sample is 10.68 g. Upon combustion it gives 16.01 g CO2 and 4.37 g H2O

Q: A compound contains only C, H, and N. Combustion of 35.0 mg of the compound produces 33.5 mg CO2…

A: Given: compound contains only C, H, and N mass of compound = 35 mg mass of CO2 produced = 33.5 mg…

Q: Menthol is a flavoring agent extracted from peppermint oil. It contains C, H, and O. In one…

A: The combustion of menthol is given by

Q: A compound contains only carbon, hydrogen, nitrogen, and oxygen. Combustion of 0.157 g sample of the…

Q: An iron-containing compound is 20.1% Fe, 11.5% S, 63.3% O, and 5.1% H. What is the empirical formula…

A: First of all, we will calculate the number of moles of each element from given mass and then, we…

Q: Combustion of a 0.66 g sample of a compound containing only carbon, hydrogen, and oxygen produced…

A: Weight of the sample = 0.66 g Weight of CO2 = 1.452 g Weight of H2O = 0.792 g

Q: Caffeine a stimulant found in coffee, tea and chocolate is composed of C, H, N and O. Combustion of…

Q: The empirical formula for a compound is CH20, and the molar mass is 180.2 g/mol. Which is the…

A: The question is about to determine the Molecular Formula of the Compound from the given Empirical…

Q: A compound has the empirical formula CH,O and a molar mass of approximately-180. g/mol. What is its…

A: Divide the molar mass of the compound by the empirical formula mass. The result should be a whole…

Q: Combustion analysis of 1.200 g of an unknown compound containing carbon, hydrogen, and oxygen…

A: molar mass of CO2 = 44 g/molmolar mass of carbon = 12 g/mol1 CO2 has 1 C in itmolar mass of H2O = 18…

Q: In a quantitative analysis study, 4.624 grams of a hydrocarbon (which contains carbon and hydrogen…

A: Since in the each molecule of CO2 we have 1 atom of C and in each molecule of H2O we have 2 H atoms…

Concept explainers

Mole Concept

Mole concept is a method to determine the amount of any substance that consists of some elemental particles using a grouping unit called ‘mole’. The mole concept enables one to handle the large amount of small elementary particles. The mole concept can be used in many calculations related to mole calculation, molar amount, mole ratio, and so on, which are significant in chemistry.

Question

02:19:04
Time Remaining
Return
4
Calculate the empirical formula of a substance which contains 0.780 g of C, 0.0654g of H, and 0.693 g of O.
C3H,O2
C5H3O2
C3H50
C3H3O2
C4H6O3
C2H3Q
C3H3O2

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step by step

Solved in 2 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.

Similar questions

A Boron and hydrogen form an extensive family of compounds, and the diagram below shows how they are related by reaction. The following table gives the weight percent of boron in each of the compounds. Derive the empirical and molecular formulas of compounds A-E.
Gold is produced electrochemically from an aqueous solution of Au(CN)2 containing an excess of CN. Gold metal and oxygen gas are produced at the electrodes. What amount (moles) of O2 will be produced during the production of 1.00 mole of gold?
13
I have attached an image. Thank you.
#55
10:05 A ull 5G Question 12 of 15 Submit Consider the following balanced chemical equation: Ca(NO3)2 (aq) + LİSO, (aq) → 2 LİNO; (aq) + CaSO, (s) If 10.0 g of Ca(NO3)2 are mixed with 10.0 g of Li,SO4, how many grams of CaSO, can be produced? A) 8.30 g B) 12.4 g C) 20.7 g D) 4.10 g Tap here or pull up for additional resources
9-please fast
10
The reaction between SO3 (g) and CO2 (g) is based on the chemical equation below. 2 SO3 (g) + CO2 (g) = CS2 (g) + 4 O2 (g) At 500 oC, we mix 0.20 mol SO3 (g) 0.25 mol CO2 (g) and 1.20 mol O2 (g) (without CS2 (g)) initially in a 1-L bottle. After the reaction reaches equilibrium, the amount of SO3 (g) becomes 0.12 mol. Determine the value of the equilibrium constant of the above reaction (with 2 significant figures).
Pyruvic acid, HC3H3O3, is involved in cell metabolism. It can be assayed for (that is, the amount of it determined) by using a yeast enzyme. The enzyme makes the following reaction go to completion: HC3H3O3(aq) h C2H4O(aq) + CO2(g) If a sample containing pyruvic acid gives 21.2 mL of carbon dioxide gas, CO2, at 349 mmHg and 30°C, how many grams of pyruvic acid are there in the sample?
6
4. A common experiment at Science Fairs is the demonstration of a volcano using a mixture of baking soda, NaHCO3(s), and vinegar, CH₂COOH(aq), with the reaction: NaHCO3(s) + CH3COOH(aq)- CO2(g) + H₂O(l) + Nat(aq) + CH3COO(aq) where the heavier CO2 gas displaces the liquid mixture to the top of the container to simulate lava overflowing. If the volume of the reaction vessel is 0.500 L and the pressure is 0.997 atm and 298 K. given 50.5 ml of 0.351 M CH3COOH() in water, what mass of NaHCO3(s) is required to fill the bottle with CO2 gas?