Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![**Calculating the Double Integral**
In this section, we will compute a given double integral over a defined region. The double integral in question is:
\[ \iint_R 11x \sin(x + y) \, dA \]
Where the region \( R \) is defined as:
\[ R = \left[0, \frac{\pi}{6}\right] \times \left[0, \frac{\pi}{3}\right] \]
This indicates that our region \( R \) is a rectangle in the \( xy \)-plane where \( x \) ranges from 0 to \( \frac{\pi}{6} \) and \( y \) ranges from 0 to \( \frac{\pi}{3} \).
To evaluate this double integral, we will integrate over \( x \) and \( y \) within the given limits. Here's the detailed breakdown of the region \( R \) and how the bounds are set for both \( x \) and \( y \):
1. **Integral Bounds for \( x \)**: \( 0 \leq x \leq \frac{\pi}{6} \)
2. **Integral Bounds for \( y \)**: \( 0 \leq y \leq \frac{\pi}{3} \)
The integral can be expressed and computed as:
\[ \int_{0}^{\frac{\pi}{3}} \int_{0}^{\frac{\pi}{6}} 11x \sin(x + y) \, dx \, dy \]
This format makes it evident that we will first integrate with respect to \( x \) from 0 to \( \frac{\pi}{6} \), and then integrate with respect to \( y \) from 0 to \( \frac{\pi}{3} \).
The rectangular bounds have been clearly specified to simplify the computation of the double integral, ensuring that all variables are confined within the given intervals.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F97b7422a-52f7-4bc4-acdc-28b7d7bc43e4%2F34135f64-f59a-4d91-9e8b-c8d3509d1fc7%2Fdnv0exv_processed.png&w=3840&q=75)
Transcribed Image Text:**Calculating the Double Integral**
In this section, we will compute a given double integral over a defined region. The double integral in question is:
\[ \iint_R 11x \sin(x + y) \, dA \]
Where the region \( R \) is defined as:
\[ R = \left[0, \frac{\pi}{6}\right] \times \left[0, \frac{\pi}{3}\right] \]
This indicates that our region \( R \) is a rectangle in the \( xy \)-plane where \( x \) ranges from 0 to \( \frac{\pi}{6} \) and \( y \) ranges from 0 to \( \frac{\pi}{3} \).
To evaluate this double integral, we will integrate over \( x \) and \( y \) within the given limits. Here's the detailed breakdown of the region \( R \) and how the bounds are set for both \( x \) and \( y \):
1. **Integral Bounds for \( x \)**: \( 0 \leq x \leq \frac{\pi}{6} \)
2. **Integral Bounds for \( y \)**: \( 0 \leq y \leq \frac{\pi}{3} \)
The integral can be expressed and computed as:
\[ \int_{0}^{\frac{\pi}{3}} \int_{0}^{\frac{\pi}{6}} 11x \sin(x + y) \, dx \, dy \]
This format makes it evident that we will first integrate with respect to \( x \) from 0 to \( \frac{\pi}{6} \), and then integrate with respect to \( y \) from 0 to \( \frac{\pi}{3} \).
The rectangular bounds have been clearly specified to simplify the computation of the double integral, ensuring that all variables are confined within the given intervals.
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