Calculate the Derivative k(u) == are sec(u) 3u + 2

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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01:57
Calculate the Derivative
○ k' (u) =
(3+2) - 3are sec(u)
(3u+ 2)²
Rafique on 7/28/23, 01:57
(+2)-3x+2
(3u+2)²
(-+)-3are sec(u)
(3u + 2)2
(-)-3are sec(u)
(3u + 2)²
\ovo-T
14
-3are sec(u)
(3u + 2)²
и
k (u) =
are sec(u)
3u + 2
☆
4G 51
All Media
€
Ep
Transcribed Image Text:01:57 Calculate the Derivative ○ k' (u) = (3+2) - 3are sec(u) (3u+ 2)² Rafique on 7/28/23, 01:57 (+2)-3x+2 (3u+2)² (-+)-3are sec(u) (3u + 2)2 (-)-3are sec(u) (3u + 2)² \ovo-T 14 -3are sec(u) (3u + 2)² и k (u) = are sec(u) 3u + 2 ☆ 4G 51 All Media € Ep
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