Calculate the critical depth, and compare them with the conjugate depths observed in the jump.
Calculate the critical depth, and compare them with the conjugate depths observed in the jump.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Please answer the third question using the table with the given information
![**Part 3 – Hydraulic Jump and Critical Depth – C4 Flume**
**Channel width:** 7.6 cm
**Flume Slope:** 3%
**Distance between gauges:** 100 cm
---
### Jump Condition Table:
| Jump Condition | y1 (cm) | y2 (cm) | z1 (cm) | z2 (cm) | Q (cm³/sec) | V1 (cm/sec) | V2 (cm/sec) | Computed HJ (cm) | % Loss Based on Upstream Energy |
|----------------|---------|---------|---------|---------|-------------|-------------|-------------|------------------|----------------------------------|
| Direct | 1.59 | 11 | 3 | 0 | 1570 | 129.924 | 18.78 | 9.41 | 15.26 |
---
**Computed yc:** 3.5 cm
### Calculations:
- **V1 Calculation:**
\[
V_1 = \frac{Q}{by_1} = \frac{1570}{7.6 \times 1.59} = 129.924 \text{ cm/sec}
\]
- **V2 Calculation:**
\[
V_2 = \frac{Q}{b(1)} = \frac{1570}{7.6 \times 11} = 18.78 \text{ cm/sec}
\]
- **Hydraulic Jump (HJ):**
\[
HJ = y_2 - y_1 = 11 - 1.59 = 9.41 \text{ cm}
\]
- **% Loss in Energy:**
\[
\% E_l = \frac{E_{\text{ups}} - E_{\text{dls}}}{E_{\text{ups}}} \times 100 = \frac{13.1936 - 11.18}{13.1936} \times 100 = 15.26\%
\]
- **Energy Calculation:**
- **Upstream Energy (Eups):**
\[
E_{\text{ups}} = y_1 + z_1 + \frac{V_1^2}{2g} = 1.59 + 3 + \frac{129.924^](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Feb0db590-5d37-48a1-bf5a-623f4987797d%2F29f6f291-3394-44e7-be82-4645080d9f9e%2Fwqpna7_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Part 3 – Hydraulic Jump and Critical Depth – C4 Flume**
**Channel width:** 7.6 cm
**Flume Slope:** 3%
**Distance between gauges:** 100 cm
---
### Jump Condition Table:
| Jump Condition | y1 (cm) | y2 (cm) | z1 (cm) | z2 (cm) | Q (cm³/sec) | V1 (cm/sec) | V2 (cm/sec) | Computed HJ (cm) | % Loss Based on Upstream Energy |
|----------------|---------|---------|---------|---------|-------------|-------------|-------------|------------------|----------------------------------|
| Direct | 1.59 | 11 | 3 | 0 | 1570 | 129.924 | 18.78 | 9.41 | 15.26 |
---
**Computed yc:** 3.5 cm
### Calculations:
- **V1 Calculation:**
\[
V_1 = \frac{Q}{by_1} = \frac{1570}{7.6 \times 1.59} = 129.924 \text{ cm/sec}
\]
- **V2 Calculation:**
\[
V_2 = \frac{Q}{b(1)} = \frac{1570}{7.6 \times 11} = 18.78 \text{ cm/sec}
\]
- **Hydraulic Jump (HJ):**
\[
HJ = y_2 - y_1 = 11 - 1.59 = 9.41 \text{ cm}
\]
- **% Loss in Energy:**
\[
\% E_l = \frac{E_{\text{ups}} - E_{\text{dls}}}{E_{\text{ups}}} \times 100 = \frac{13.1936 - 11.18}{13.1936} \times 100 = 15.26\%
\]
- **Energy Calculation:**
- **Upstream Energy (Eups):**
\[
E_{\text{ups}} = y_1 + z_1 + \frac{V_1^2}{2g} = 1.59 + 3 + \frac{129.924^
Transcribed Image Text:### Questions for Discussion
1. **Summarize the energy loss across the jump that you created expressed as a percentage of the upstream energy. Do you consider this significant?**
2. **How is the energy dissipated in the jump? How can jumps be used in engineering practice?**
3. **Calculate the critical depth, and compare them with the conjugate depths observed in the jump.**
---
This educational material presents questions aimed at examining the concepts of energy loss, energy dissipation, and critical depth in hydraulic jumps. The focus is on understanding the percentage of energy loss relative to upstream conditions, the methods of energy dissipation, and the practical applications in engineering. Additionally, the calculation and comparison of critical and conjugate depths provide insights into fluid dynamics and hydraulic systems.
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