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Calculate the change in internal energy (in kJ) when a 5 kg Cast Iron pot is heated from 20°C (65°F) to 210°C (410°F).

Calculate the change in internal energy (in kJ) when a 5 kg Cast Iron pot is heated from 20°C (65°F) to 210°C (410°F).

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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**Problem Statement:** 1. Calculate the change in internal energy (in kJ) when a 5 kg cast iron pot is heated from 20°C (65°F) to 210°C (410°F). **Explanation:** To calculate the change in internal energy, we can use the formula: \[ \Delta U = mc\Delta T \] Where: - \( m \) is the mass of the object (5 kg) - \( c \) is the specific heat capacity of cast iron (approximately 0.46 kJ/kg°C) - \( \Delta T \) is the change in temperature (210°C - 20°C) Substitute the values and calculate to find the change in internal energy. This problem involves basic thermodynamics concepts and is useful in understanding how energy transfer works during heating processes.
Transcribed Image Text:**Problem Statement:** 1. Calculate the change in internal energy (in kJ) when a 5 kg cast iron pot is heated from 20°C (65°F) to 210°C (410°F). **Explanation:** To calculate the change in internal energy, we can use the formula: \[ \Delta U = mc\Delta T \] Where: - \( m \) is the mass of the object (5 kg) - \( c \) is the specific heat capacity of cast iron (approximately 0.46 kJ/kg°C) - \( \Delta T \) is the change in temperature (210°C - 20°C) Substitute the values and calculate to find the change in internal energy. This problem involves basic thermodynamics concepts and is useful in understanding how energy transfer works during heating processes.
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