Calculate the centripetal force on the end of a 122-m (radius) wind turbine blade that is rotating at 0.5 rev/s. Assume the mass is 6 kg. F₁ = Question Help: Submit Question N Read 1 Read 2

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Title: Calculating Centripetal Force on a Wind Turbine Blade

**Problem Statement:**
Calculate the centripetal force on the end of a 122 cm (radius) wind turbine blade that is rotating at 0.5 rev/s. Assume the mass is 6 kg.

**Formula:**
The centripetal force \( F_c \) can be calculated using the formula:
\[ F_c = m \cdot \omega^2 \cdot r \]

Where:
- \( m \) is the mass of the object in kilograms.
- \( \omega \) is the angular velocity in radians per second.
- \( r \) is the radius in meters.

**Given:**
- Radius \( r = 122 \) cm \( = 1.22 \) meters
- Rotational speed = 0.5 revolutions per second
- Mass \( m = 6 \) kg

**Steps:**

1. **Convert rotational speed to angular velocity:**
   \[ \omega = 2\pi \cdot \text{rotational speed} = 2\pi \cdot 0.5 \, \text{rad/s} = \pi \, \text{rad/s} \]

2. **Substitute the known values into the formula:**
   \[ F_c = 6 \, \text{kg} \cdot (\pi \, \text{rad/s})^2 \cdot 1.22 \, \text{m} \]

3. **Calculate the centripetal force:**
   \[ F_c = 6 \cdot \pi^2 \cdot 1.22 \]
   \[ F_c \approx 6 \times 9.87 \times 1.22 \]
   \[ F_c \approx 72.124 \, \text{N} \]

**Resources:**

- **Question Help:**
  - [Read 1]
  - [Read 2]

**Hint:**
- Additional hints can be viewed by clicking on [Hint 1].

**Action:**
- Click "Submit Question" to check your answer.
Transcribed Image Text:Title: Calculating Centripetal Force on a Wind Turbine Blade **Problem Statement:** Calculate the centripetal force on the end of a 122 cm (radius) wind turbine blade that is rotating at 0.5 rev/s. Assume the mass is 6 kg. **Formula:** The centripetal force \( F_c \) can be calculated using the formula: \[ F_c = m \cdot \omega^2 \cdot r \] Where: - \( m \) is the mass of the object in kilograms. - \( \omega \) is the angular velocity in radians per second. - \( r \) is the radius in meters. **Given:** - Radius \( r = 122 \) cm \( = 1.22 \) meters - Rotational speed = 0.5 revolutions per second - Mass \( m = 6 \) kg **Steps:** 1. **Convert rotational speed to angular velocity:** \[ \omega = 2\pi \cdot \text{rotational speed} = 2\pi \cdot 0.5 \, \text{rad/s} = \pi \, \text{rad/s} \] 2. **Substitute the known values into the formula:** \[ F_c = 6 \, \text{kg} \cdot (\pi \, \text{rad/s})^2 \cdot 1.22 \, \text{m} \] 3. **Calculate the centripetal force:** \[ F_c = 6 \cdot \pi^2 \cdot 1.22 \] \[ F_c \approx 6 \times 9.87 \times 1.22 \] \[ F_c \approx 72.124 \, \text{N} \] **Resources:** - **Question Help:** - [Read 1] - [Read 2] **Hint:** - Additional hints can be viewed by clicking on [Hint 1]. **Action:** - Click "Submit Question" to check your answer.
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