Calculate the boiling point of 5 grams glucose (chemical formula C6H1206) when dissolved in 1.5 kg of water. The ebuilloscopic constant of water is 0.52°C/m and its boiling point is 100°C. 100.01 degrees Celsius 50.75 degrees Celsius 150.5 degrees Celsius 125.00 degrees Celsius

Calculate the boiling point of 5 grams glucose (chemical formula C6H1206) when dissolved in 1.5 kg of water. The ebuilloscopic constant of water is 0.52°C/m and its boiling point is 100°C. 100.01 degrees Celsius 50.75 degrees Celsius 150.5 degrees Celsius 125.00 degrees Celsius

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Solutions

Solutions can be considered as homogeneous mixtures which contain two or more than two chemical substances. The chemical substance which is the greater part is defined as solvent. And the chemical substance that is dissolved in a solvent is referred to as solute. Solution chemistry plays an important role in chemistry since it supports many commercial applications of solutions.

Question

Calculate the boiling point of 5 grams glucose (chemical formula
C6H1206) when dissolved in 1.5 kg of water. The ebuilloscopic constant
of water is 0.52°C/m and its boiling point is 100°C.
100.01 degrees Celsius
50.75 degrees Celsius
150.5 degrees Celsius
125.00 degrees Celsius

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