Calculate the approximate volume of vinegar to react with 25 mL of 0.1 M NaOH. Trial 1 Trial 2 Trial 3 Mass of flask (g) 120.056 1as.237 128.321 Mass of flask + vinegar sample (8) Mass of vinegar sample (g) SIE:Sと」 131.911 008 LO'E 3.59000 3.0Cco0 Initial buret reading of NaOH (mL) Final buret reading of NaOH 25.25 24.95 26.05 (u) Volume of NaOH dispensed 25.25 24.95 [NAOH] (M), average from Part Moles of NaOH dispensed O. 00 2525 mol 0.002495 mel0.001cosmo Moles of acetic acid in vinegar 0.002525 mol 0.00249 5 mollo.002COS mol sample Mass of acetic acid in vinegar sample (g) Per ent by mass of acetic acid in vinegar sample (%) Average percent by mass of acetic acid in vinegar sample (%) Standard deviation of percent by mass of acetic acid in vinegar sample (%)

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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How do I find the mass of acetic acid in a vinegar sample in grams, with the correct amount of signifcant figures? 

CHEM 181 Experiment #5
Part B
Calculate the approximate volume of vinegar to react with 25 mL of 0.1 M NAOH.
Trial 1
Trial 2
Trial 3
Mass of flask (g)
120.056
125.237
Mass of flask + vinegar sample
(3)
Mass of vinegar sample (g)
SIE:3と1
131.911
123.122
3.0GCO
008LO
Initial buret reading of NaOH
(m)
Final buret reading of NaOH
25.25
24.95
2 6.05
(m)
Volume of NaOH dispensed
(mL)
[NaOH] (M), average from Part
25.25
24.95
O. 100
A.
Moles of NaOH dispensed
Oi 002525 mol 0.00249 Sma0.002cos mol
Moles of acetic acid in vinegar
0.002525 mol 0.00249S mollo.002GOS mol
sample
Mass of acetic acid in vinegar
sample (g)
Percent by mass of acetic acid in
vinegar sample (%)
Mass Sar
Average percent by mass of acetic acid in vinegar sample (%)
Standard deviation of percent by mass of acetic acid in vinegar sample (%).
Transcribed Image Text:CHEM 181 Experiment #5 Part B Calculate the approximate volume of vinegar to react with 25 mL of 0.1 M NAOH. Trial 1 Trial 2 Trial 3 Mass of flask (g) 120.056 125.237 Mass of flask + vinegar sample (3) Mass of vinegar sample (g) SIE:3と1 131.911 123.122 3.0GCO 008LO Initial buret reading of NaOH (m) Final buret reading of NaOH 25.25 24.95 2 6.05 (m) Volume of NaOH dispensed (mL) [NaOH] (M), average from Part 25.25 24.95 O. 100 A. Moles of NaOH dispensed Oi 002525 mol 0.00249 Sma0.002cos mol Moles of acetic acid in vinegar 0.002525 mol 0.00249S mollo.002GOS mol sample Mass of acetic acid in vinegar sample (g) Percent by mass of acetic acid in vinegar sample (%) Mass Sar Average percent by mass of acetic acid in vinegar sample (%) Standard deviation of percent by mass of acetic acid in vinegar sample (%).
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