Answered: Calculate the amount of solid( in…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

Calculate the amount of solid( in grams) that is produced when 21.00mL of 0.1500 M lead(IV) chlorate is mixed with 25.00mL of 0.1400 M sodium carbonate. Write the balanced molecular and net ionic equations for this reaction. STATE THE SPECATOR IONS LEFT IN SOLUTION.

Expert Solution

Net Ionic equation

The balanced molecular equation will be,
Pb(ClO₃)₄ (aq) + 2Na₂CO₃ (aq) → Pb(CO₃)₂ (s) + 4NaClO₃ (aq)
The Complete Ionic equation will be,
Pb⁺⁴(aq) + 4 ClO₃^- (aq) + 4 Na⁺(aq) + 2 CO₃^2- (aq) $\to$ Pb(CO₃)₂ (s) + 4 Na⁺(aq) + 4ClO₃^-(aq)
Spectator ions are the ions that are present on both sides of the reactions.
Spectator ions left in the solution are: Na⁺ , ClO₃^-
Now remove spectator ions from the equation and write the equation with the remaining ions which will give you net ionic equation.

Net Ionic equation:
$P b^{+ 4} (a q) + 2 C {O_{3}}^{2 -} (a q) \to P b (C O$ ₃)2 (s)

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