Help Calculate the AH (in kJ) for the following reaction, the preparation of nitrous acid HNO2:HCl(g) + NANO2(s) → HNO2(1) + NaC((s)Use the following thermochemical equations:2NACI(s) + H20(1) → 2HCI(g) + Na20(s) AH = +507.31 kJNO(g) + NO2(g) + Na20(s) → 2NANO2(s)AH = -427.14 kJNO(g) + NO2(g) → N20(g) + O2(g)AH = -42.68 kJ2HNO2(1) → N20(g) + O2(g) + H20(I)AH = +34.35 kJLütfen birini seçin:a. -98.12b. -53.89C. +165.23d. -78.59

Given: 2NaCl(s)+H2O(l)→2HCl(g)+Na2O(s) ∆H=+507.31 kJ.... (1) NO(g)+NO2(g)+Na2O(s)→2NaNO2(s)…

Calculate the AH (in kJ) for the following reaction, the preparation of nitrous acid HNO2: HCI(g) + NaNO2(s) → HNO2(1) + NaCl(s) Use the following thermochemical equations: 2NACI(s) + H2O(I) → 2HCI(g) + Na20(s) AH = +507.31 kJ NO(g) + NO2(g) + Na20(s) → 2NaNO2(s)AH = -427.14 kJ %3D NO(g) + NO2(g) –→ N2O(g) + O2(g) AH = -42.68 kJ 2HNO2(1) → N20(g) + O2(g) + H2O(I) AH = +34.35 kJ

Calculate the AH (in kJ) for the following reaction, the preparation of nitrous acid HNO2: HCI(g) + NaNO2(s) → HNO2(1) + NaCl(s) Use the following thermochemical equations: 2NACI(s) + H2O(I) → 2HCI(g) + Na20(s) AH = +507.31 kJ NO(g) + NO2(g) + Na20(s) → 2NaNO2(s)AH = -427.14 kJ %3D NO(g) + NO2(g) –→ N2O(g) + O2(g) AH = -42.68 kJ 2HNO2(1) → N20(g) + O2(g) + H2O(I) AH = +34.35 kJ

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

Help

Calculate the AH (in kJ) for the following reaction, the preparation of nitrous acid HNO2:
HCl(g) + NANO2(s) → HNO2(1) + NaC((s)
Use the following thermochemical equations:
2NACI(s) + H20(1) → 2HCI(g) + Na20(s) AH = +507.31 kJ
NO(g) + NO2(g) + Na20(s) → 2NANO2(s)AH = -427.14 kJ
NO(g) + NO2(g) → N20(g) + O2(g)
AH = -42.68 kJ
2HNO2(1) → N20(g) + O2(g) + H20(I)
AH = +34.35 kJ
Lütfen birini seçin:
a. -98.12
b. -53.89
C. +165.23
d. -78.59

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