Calculate the AE of the electron of a hydrogen atom as the electron drops from the n=5 state to the n=3 state. ル3 1. +2.91 x 10-20 2. -2.91 x 10-20 You forgot to square the n's 3. +1.55 x 10-19 You put n's in the wrong order 4. -1.55 x 10-19 AE: -R. ( -) UK UNIVERSITY OF KENTUCKY' (3² 32 52 Department of Chemistry

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   Hi so the problem goes:

"Calculate the change in energy of an electron of a hydrogen atom as the electron drops from the n=5 states to the n = 3 state."

    I understand the problem as far as the screenshot I have attached is showing, but when I plug the numbers in I get -0.13625 and then I assumed the answer would be 1.36 x 10^18 or something like this. I am told the answer is -1.55 x 10^-19. I just don't know how (or why) it is.

Best Regards,
Gabe

Calculate the AE of the electron of a hydrogen
atom as the electron drops from the n= 5 state to
the n= 3 state.
1. +2.91 x 10-20
2. -2.91 x 10-20
You forgot to square the n’s
3. +1.55 x 10-19
You put n's in the wrong order
4. -1.55 x 10-19
AE: -R.(
UK
UNIVERSITY OF
KENTUCKY'
32
52
Department of Chemistry
Transcribed Image Text:Calculate the AE of the electron of a hydrogen atom as the electron drops from the n= 5 state to the n= 3 state. 1. +2.91 x 10-20 2. -2.91 x 10-20 You forgot to square the n’s 3. +1.55 x 10-19 You put n's in the wrong order 4. -1.55 x 10-19 AE: -R.( UK UNIVERSITY OF KENTUCKY' 32 52 Department of Chemistry
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