**Title: Analyzing Structural Loads in Floor Framing****Instruction:**Calculate the maximum values of moments and shears at each span using the American Concrete Institute (ACI) coefficients for the floor slab, the interior continuous beam, and the exterior continuous beam of the floor framing shown.For the slab, use the minimum thickness specified by the ACI when deflections are not calculated. (Using the same slab thickness for the entire floor is recommended).**Diagram Description:**The diagram presents a framing plan divided into spans and columns:- **Spans:** - \( L_1 \), \( L_2 \), and \( L_3 \) are the horizontal spans of the structure, with lengths 30 ft, 26 ft, and 30 ft, respectively. - Each section is represented as a rectangular area within the grid.- **Columns:** - Spaced vertically, labeled \( L_4 \), with a length of 12 ft each. These columns include a typical size of 12 in. x 12 in. The grid represents repeated vertical sections.**Table Details:**| Parameter | Description | Value ||------------|---------------------------------|-------|| \( L_1 \) | Span Length (ft) | 30 || \( L_2 \) | Span Length (ft) | 26 || \( L_3 \) | Span Length (ft) | 30 || \( L_4 \) | Column Length (ft) | 12 || SDL | Superimposed Dead Load (psf) | 20 || LL | Live Load (psf) | 150 || Wall | Load Factor | 1.0 || \( f'_c \) | Concrete Compressive Strength (psi) | 4000 || \( f_y \) | Yield Strength of Steel (ksi) | 60 |**Notes:**- Ensure adherence to ACI guidelines for calculating structural member sizes and reinforcements.- Use the table values to perform calculations accurately, considering all structural loads in design and analysis.

Calculating the dimension of slab: For 4 span of L4=12' the width of beam=12" Ln(slab)=12'-1212×12-1212×12 =11'For the loading slab: The self weight of slab consisting of the thickness of slab based on ACI criteria ( both the ends are continuous, and the beams are at each end). Lmin=Ln/28 =11*12/28 =4.7" =5" The self weight of slab=150*(5/12)=62.5 psf SDL=20 psf Total DL=82.5 psf LL=150 psf Wu=1.2*82.5+1.6*150 =339 psf =0.34 ksf The loading on internal beam:Assuming the self weight=12"*12" =150*12*12/144=150 lb/ft =0.15 k/ft*1.2 =0.18 k/ft Wall=1 k/ft*1.2=1.2 k/ft (factored) Load from slab=(12'12/2)*0.34=2.04 k/ft Wu=4.08+0.18+1.2=5.5 k/ft For the external beam: load from one side of slab=12*0.34/2=2.04 k/ft Weight on external beam=2.04+0.18+1.2=3.52 k/ft

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Civil Engineering

Calculate maximum values of moments and shears at each span using the ACI coefficients for the floor slab, the interior continuous beam and the exterior continuous beam of the floor framing shown. For the slab use the minimum thickness specified by the ACI when deflections are not calculated (Use the same slab thickness for the entire floor) L1 L2 L3

Calculate maximum values of moments and shears at each span using the ACI coefficients for the floor slab, the interior continuous beam and the exterior continuous beam of the floor framing shown. For the slab use the minimum thickness specified by the ACI when deflections are not calculated (Use the same slab thickness for the entire floor) L1 L2 L3

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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