Calculate [H,O*] for a 4.15 x 10-3 M HBr solution. [H,O*] = Calculate [H,O+] for a 1.60 x 10-2 M KOH solution.

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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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### Transcription for Educational Website

#### Problem Statements:

1. **Calculate \([H_3O^+]\) for a 4.15 × 10\(^{-3}\) M HBr solution.**

   \[[H_3O^+] = \underline{\hspace{60mm}} \text{M}\]

2. **Calculate \([H_3O^+]\) for a 1.60 × 10\(^{-2}\) M KOH solution.**

   \[[H_3O^+] = \underline{\hspace{60mm}} \text{M}\]

#### Explanation:

The problems require the calculation of the hydronium ion concentration, \([H_3O^+]\), for two different solutions:

- **HBr Solution:** HBr is a strong acid, which dissociates completely in water to form H\(^+\) ions. Hence, the concentration of H\(^+\) (or equvalently \([H_3O^+]\)) will be equal to the concentration of the HBr solution, which is \(4.15 \times 10^{-3}\) M.
  
- **KOH Solution:** KOH is a strong base, which dissociates completely in water to form OH\(^-\) ions. The concentration of OH\(^-\) ions will be \(1.60 \times 10^{-2}\) M. To find \([H_3O^+]\), use the relation \( [H_3O^+] \times [OH^-] = 1.0 \times 10^{-14}\) at 25°C to calculate \([H_3O^+]\).
Transcribed Image Text:### Transcription for Educational Website #### Problem Statements: 1. **Calculate \([H_3O^+]\) for a 4.15 × 10\(^{-3}\) M HBr solution.** \[[H_3O^+] = \underline{\hspace{60mm}} \text{M}\] 2. **Calculate \([H_3O^+]\) for a 1.60 × 10\(^{-2}\) M KOH solution.** \[[H_3O^+] = \underline{\hspace{60mm}} \text{M}\] #### Explanation: The problems require the calculation of the hydronium ion concentration, \([H_3O^+]\), for two different solutions: - **HBr Solution:** HBr is a strong acid, which dissociates completely in water to form H\(^+\) ions. Hence, the concentration of H\(^+\) (or equvalently \([H_3O^+]\)) will be equal to the concentration of the HBr solution, which is \(4.15 \times 10^{-3}\) M. - **KOH Solution:** KOH is a strong base, which dissociates completely in water to form OH\(^-\) ions. The concentration of OH\(^-\) ions will be \(1.60 \times 10^{-2}\) M. To find \([H_3O^+]\), use the relation \( [H_3O^+] \times [OH^-] = 1.0 \times 10^{-14}\) at 25°C to calculate \([H_3O^+]\).
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