Calculate adr. -4ft a, ft/sec2 14 7 10 x, ft 10 a dx = 26.000 f/sec? Answer: -4n eTextbook and Media Hint Attempts: 2 of 2 used Using multiple attempts has impacted your score. 20% score reduction after attempt 1 Part 2 Determine the velocity vwhenx= 10 ft. a, ft/sec 14- 7 10 x, ft Answer: v= i ft/sec

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
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A particle moving along a straight line has an acceleration which varies according to position as shown. If the velocity of the particle at
the position x = -4 ft is v= 7 ft/sec, determine the velocity v when x = 10 ft.
a, ft/sec2
14
-4
10
x, ft
-6
Transcribed Image Text:A particle moving along a straight line has an acceleration which varies according to position as shown. If the velocity of the particle at the position x = -4 ft is v= 7 ft/sec, determine the velocity v when x = 10 ft. a, ft/sec2 14 -4 10 x, ft -6
10t
Calculate
a dx.
-4ft
a, ft/sec2
14
-4
7
10
x, ft
-6
10ft
Answer:
a dx =
ft?/sec?
26.000
-4n
eTextbook and Media
Hint
Attempts: 2 of 2 used
Using multiple attempts has impacted your score.
20% score reduction after attempt 1
Part 2
Determine the velocity vwhen x= 10 t.
a, ft/sec2
14
7
10
x, ft
-6
Answer: v =
ft/sec
Transcribed Image Text:10t Calculate a dx. -4ft a, ft/sec2 14 -4 7 10 x, ft -6 10ft Answer: a dx = ft?/sec? 26.000 -4n eTextbook and Media Hint Attempts: 2 of 2 used Using multiple attempts has impacted your score. 20% score reduction after attempt 1 Part 2 Determine the velocity vwhen x= 10 t. a, ft/sec2 14 7 10 x, ft -6 Answer: v = ft/sec
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