Calculate a value for the equilibrium constant for the reaction O2 (9) + O(g) = 03 (g) given hv NO2 (g) = NO(g) + O(g) K = 5.1 × 10-49 03 (g) + NO(9) = NO,(g)+ O2(9) K= 2.2 × 10-34 (Hint: When reactions are added together, the equilibrium expressions are multiplied.) K=
Calculate a value for the equilibrium constant for the reaction O2 (9) + O(g) = 03 (g) given hv NO2 (g) = NO(g) + O(g) K = 5.1 × 10-49 03 (g) + NO(9) = NO,(g)+ O2(9) K= 2.2 × 10-34 (Hint: When reactions are added together, the equilibrium expressions are multiplied.) K=
Chemistry
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Calculating the Equilibrium Constant**
Calculate a value for the equilibrium constant for the reaction:
\[ \text{O}_2(g) + \text{O}(g) \rightleftharpoons \text{O}_3(g) \]
Given:
1. \[ \text{NO}_2(g) \xrightleftharpoons{h\nu} \text{NO}(g) + \text{O}(g) \quad K = 5.1 \times 10^{-49} \]
2. \[ \text{O}_3(g) + \text{NO}(g) \rightleftharpoons \text{NO}_2(g) + \text{O}_2(g) \quad K = 2.2 \times 10^{-34} \]
*(Hint: When reactions are added together, the equilibrium expressions are multiplied.)*
\[ K = \text{(resulting equilibrium constant)} \]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F488059e9-9840-4657-993c-02629fc3cfd9%2F93246039-2a6e-4102-8786-bd024f78846d%2Fhioy67a_processed.png&w=3840&q=75)
Transcribed Image Text:**Calculating the Equilibrium Constant**
Calculate a value for the equilibrium constant for the reaction:
\[ \text{O}_2(g) + \text{O}(g) \rightleftharpoons \text{O}_3(g) \]
Given:
1. \[ \text{NO}_2(g) \xrightleftharpoons{h\nu} \text{NO}(g) + \text{O}(g) \quad K = 5.1 \times 10^{-49} \]
2. \[ \text{O}_3(g) + \text{NO}(g) \rightleftharpoons \text{NO}_2(g) + \text{O}_2(g) \quad K = 2.2 \times 10^{-34} \]
*(Hint: When reactions are added together, the equilibrium expressions are multiplied.)*
\[ K = \text{(resulting equilibrium constant)} \]
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