Homework Help is Here – Start Your Trial Now!
Science
Chemistry
Calcium phosphate (Ca3(PO4)2) is a chemical that can be added during water treatment and the chemical undergoes the following reaction when added to water. Ca3(PO4)2 →3 Ca²+ + 2 PO³- 4 If 37 grams of 94% pure Ca3(PO4)2 is added to 55 liters (L) of water, find the calcium (Ca²+) concentration in units of milli-moles per liter (mM). Report your answer to the nearest hundredths (0.01) place.

Calcium phosphate (Ca3(PO4)2) is a chemical that can be added during water treatment and the chemical undergoes the following reaction when added to water. Ca3(PO4)2 →3 Ca²+ + 2 PO³- 4 If 37 grams of 94% pure Ca3(PO4)2 is added to 55 liters (L) of water, find the calcium (Ca²+) concentration in units of milli-moles per liter (mM). Report your answer to the nearest hundredths (0.01) place.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
See similar textbooks
icon
Related questions
Question
Calcium phosphate (Ca3(PO4)2) is a chemical that can be added during water treatment and the chemical undergoes the following reaction when added to water. Ca3(PO4)23 Ca²+ + 2 PO³- If 37 grams of 94% pure Ca3(PO4)2 is added to 55 liters (L) of water, find the calcium (Ca²+) concentration in units of milli-moles per liter (mM). Report your answer to the nearest hundredths (0.01) place.
Transcribed Image Text:Calcium phosphate (Ca3(PO4)2) is a chemical that can be added during water treatment and the chemical undergoes the following reaction when added to water. Ca3(PO4)23 Ca²+ + 2 PO³- If 37 grams of 94% pure Ca3(PO4)2 is added to 55 liters (L) of water, find the calcium (Ca²+) concentration in units of milli-moles per liter (mM). Report your answer to the nearest hundredths (0.01) place.
Expert Solution
Step 1: Given

Mass of Ca3(PO4)2 = 37 g = m

percentage purity = 94 %

Actual mass of Ca3(PO4)2 = M

equals space m space cross times space 94 over 100 equals 37 g space cross times space 94 over 100 equals 34.78 space g


steps

Step by step

Solved in 3 steps with 2 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Knowledge Booster
Stoichiometry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Chemistry
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Organic Chemistry
Organic Chemistry
Chemistry
ISBN:
9780078021558
Author:
Janice Gorzynski Smith Dr.
Publisher:
McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
Elementary Principles of Chemical Processes, Bind…
Elementary Principles of Chemical Processes, Bind…
Chemistry
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY
SEE MORE TEXTBOOKS