Caden is a perfectionist.  He needs to make 40 widgets.  Unfortunately, each time Caden attempts to make a widget, there is only a 10% chance the widget will survive Caden's stringent standards.   Let X be the number of sub-standard widgets Caden will make before he makes 40 "perfect" widgets.  Then X has a negative binomial distribution with parameters r = 40 and p = 0.10.   ------------------------------------------------------------------------------------------   What is the probability that Caden makes over 300 subpar widgets?  P(X>300) =  % Express answer as a percent, rounding to the nearest integer.   Suppose that Caden loses $0.25 for each subpar widget he produces.  Then $0.25X represents the amount Caden loses to subpar widgets. Determine E(0.25X) =  Determine Var(0.25X)=

MATLAB: An Introduction with Applications
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Author:Amos Gilat
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Chapter1: Starting With Matlab
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Caden is a perfectionist.  He needs to make 40 widgets.  Unfortunately, each time Caden attempts to make a widget, there is only a 10% chance the widget will survive Caden's stringent standards.  

Let X be the number of sub-standard widgets Caden will make before he makes 40 "perfect" widgets.  Then X has a negative binomial distribution with parameters r = 40 and p = 0.10.

 

------------------------------------------------------------------------------------------

 

What is the probability that Caden makes over 300 subpar widgets?  P(X>300) =  %

Express answer as a percent, rounding to the nearest integer.

 

Suppose that Caden loses $0.25 for each subpar widget he produces.  Then $0.25X represents the amount Caden loses to subpar widgets.

Determine E(0.25X) = 

Determine Var(0.25X)=

Caden is a perfectionist. He needs to make 40 widgets. Unfortunately, each time Caden attempts to make a
widget, there is only a 10% chance the widget will survive Caden's stringent standards.
Let X be the number of sub-standard widgets Caden will make before he makes 40 "perfect" widgets. Then X has a
negative binomial distribution with parameters r = 40 and p = 0.10.
What is the probability that Caden makes over 300 subpar widgets? P(X>300) =
Express answer as a percent, rounding to the nearest integer.
Suppose that Caden loses $0.25 for each subpar widget he produces. Then $0.25X represents the amount Caden
loses to subpar widgets.
Determine E(0.25X) =
Determine Var(0.25X) =
Answers will be integers, do not include units of measurement.
Transcribed Image Text:Caden is a perfectionist. He needs to make 40 widgets. Unfortunately, each time Caden attempts to make a widget, there is only a 10% chance the widget will survive Caden's stringent standards. Let X be the number of sub-standard widgets Caden will make before he makes 40 "perfect" widgets. Then X has a negative binomial distribution with parameters r = 40 and p = 0.10. What is the probability that Caden makes over 300 subpar widgets? P(X>300) = Express answer as a percent, rounding to the nearest integer. Suppose that Caden loses $0.25 for each subpar widget he produces. Then $0.25X represents the amount Caden loses to subpar widgets. Determine E(0.25X) = Determine Var(0.25X) = Answers will be integers, do not include units of measurement.
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