cademy Justify triangle congruence Here is a rough outline of a proof that AABC E ADEF: 1 We can mapAABC using a sequence of rigid transformations so that A' = D and B' = E. (Show drawing 2. If C and F are on the same side of DE, then C = F. [Show drawing.) 3. If C and F are on opposite sides of DÉ, then we reflect AA' B'C' across DÉ and then C" =F. A" = D and B" = E.[Show drawing } TATUS What is the justification that C" = F in step 2? Choose 1 answer: C' and F are the same distance from E along the same ray. Both C and F lie on intersection points of circles centered at D and E with radii DF and EF, respectively. There are two such possible points, one on each side of DE. C' and F are at the intersection of the same pair of rays. Report a problem Stuck? Watch a video or use a hint. Do 4 problems 000 Check

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
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Khan Academy
Justify triangle congruence
Here is a rough outline of a proof that AABC E ADEF:
1 We can map AABC using a sequence of rigid transformations so that A' = D and B' = E.
(Show drawing.
2. If C' and F are on the same side of DE, then C = F. [Show drawing.)
3. If C and F are on opposite sides of DÉ, then we reflect AA' B'C' across DE and then C" = F.
A" = D and B" = E.[Show drawing)
Ass
TATUS
What is the justification that C" = F in step 2?
Choose 1 answer:
MS
Ass
C' and F are the same distance from E along the same ray.
See
Both C and F lie on intersection points of circles centered at D and E with radii DF and EF.
respectively. There are two such possible points, one on each side of DE.
MY
C' and F are at the intersection of the same pair of rays.
Co
MY
Report a problem
Stuck? Watch a video or use a hint.
Pro
Do 4 problems Coo0
Check
Pro
Transcribed Image Text:Khan Academy Justify triangle congruence Here is a rough outline of a proof that AABC E ADEF: 1 We can map AABC using a sequence of rigid transformations so that A' = D and B' = E. (Show drawing. 2. If C' and F are on the same side of DE, then C = F. [Show drawing.) 3. If C and F are on opposite sides of DÉ, then we reflect AA' B'C' across DE and then C" = F. A" = D and B" = E.[Show drawing) Ass TATUS What is the justification that C" = F in step 2? Choose 1 answer: MS Ass C' and F are the same distance from E along the same ray. See Both C and F lie on intersection points of circles centered at D and E with radii DF and EF. respectively. There are two such possible points, one on each side of DE. MY C' and F are at the intersection of the same pair of rays. Co MY Report a problem Stuck? Watch a video or use a hint. Pro Do 4 problems Coo0 Check Pro
Khan Academy
Justify triangle congruence
Below are AABC and ADEF.We assume that AB =DE, BC = EF, and mLB=mZE.
E
F
B
Ass
TATUS
Here is a rough outline of a proof that AABC E ADEF
MS
1 We can map AABC using a sequence of rigid transformations so that A' =D and B' = E.
Show drawing
Ass
2. If C" and F are on the same side of DE. then C = F. IShow drowing.
See
3. If C" and F are on opposite sides of DE. then we reflect A.A' B'C across DE and then C" = F.
A" = Dand B" = E. Show drawing
MY
What is the justification that C" = F in step 2?
Choose 1 answer:
C and F are the same distance from E along the same ray.
Do 4 problems
Transcribed Image Text:Khan Academy Justify triangle congruence Below are AABC and ADEF.We assume that AB =DE, BC = EF, and mLB=mZE. E F B Ass TATUS Here is a rough outline of a proof that AABC E ADEF MS 1 We can map AABC using a sequence of rigid transformations so that A' =D and B' = E. Show drawing Ass 2. If C" and F are on the same side of DE. then C = F. IShow drowing. See 3. If C" and F are on opposite sides of DE. then we reflect A.A' B'C across DE and then C" = F. A" = Dand B" = E. Show drawing MY What is the justification that C" = F in step 2? Choose 1 answer: C and F are the same distance from E along the same ray. Do 4 problems
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