cable in the position shown, i.e., so segment BC rema horizontal. -1. Determine the tension in each segment of the cable ad the distance yp- E 2 m YD 3 m 7 m 8 kN 2 m - 5 m- m 1.5m 2 kN to Prob. 5-3 4 m 5 m -3 m 4 kN *5-4. The cable supports the loading shown. Determ the distance x and the tension in cable BC. Set P = 100 Prob. 5–1 2. The cable supports the loading shown. Determine the agnitude of the vertical force P so that yc = 6 ft. 5-5. The cable supports the loading shown. Determ the magnitude of the horizontal force P so that x = 6 ft 8 ft- – 5 ft – 5 ft 3 ft 8 ft 3k 400 lb

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
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Sec. 5.1-5.2
5-3. Determine the forces P, and P2 needed to hold the
cable in the position shown, i.e., so segment BC remains
horizontal.
5-1. Determine the tension in each segment of the cable
and the distance yD-
E
2 m
YD
3 m
7 m
B.
8 kN
B.
2m
-4 m
- 5 m-
4 m
2 kN
Prob. 5–3
4 m
5 m
3 m
4 kN
*5-4. The cable supports the loading shown. Determine
the distance x and the tension in cable BC. Set P = 100 lb.
Prob. 5–1
5-2. The cable supports the loading shown. Determine the
magnitude of the vertical force P so that yc = 6 ft.
5-5. The cable supports the loading shown. Determine
the magnitude of the horizontal force P so that x = 6 ft.
8 ft
- 5 ft -
5 ft
A
D.
3 ft
B
8 ft
3k
400 Ib
2 ft
2 ft
Transcribed Image Text:Sec. 5.1-5.2 5-3. Determine the forces P, and P2 needed to hold the cable in the position shown, i.e., so segment BC remains horizontal. 5-1. Determine the tension in each segment of the cable and the distance yD- E 2 m YD 3 m 7 m B. 8 kN B. 2m -4 m - 5 m- 4 m 2 kN Prob. 5–3 4 m 5 m 3 m 4 kN *5-4. The cable supports the loading shown. Determine the distance x and the tension in cable BC. Set P = 100 lb. Prob. 5–1 5-2. The cable supports the loading shown. Determine the magnitude of the vertical force P so that yc = 6 ft. 5-5. The cable supports the loading shown. Determine the magnitude of the horizontal force P so that x = 6 ft. 8 ft - 5 ft - 5 ft A D. 3 ft B 8 ft 3k 400 Ib 2 ft 2 ft
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