C3H4(g) + 4 O2(g) → 3 CO2(g) + 2 H2O(g) If 15.0 grams of C3H4(g) are placed in a 5.00L container at 350. K and allowed to react with CAcess O2(g) for 20 minutes, the partial pressure of CO2(g) is measured to be 4.50 atm. what mass of C3H4 will be left ? (Ideal gas law: PV = nRT, R= 0.082057 L atm/mole K) %3D %3D Complete the following table and use it to help you answer the question. -> 3 CO2(g) 2 H20(g) C3H4(g) 4 O2(g) initial moles change in moles new moles (expression) new moles (numerical value)

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C3H4(g) + 4 O2(g) → 3 CO2(g) + 2 H2O(g)
If 15.0 grams of C3H4(g) are placed in a 5.00L container at 350. K and allowed to react with
CAcess O2(g) for 20 minutes, the partial pressure of CO2(g) is measured to be 4.50 atm. what
mass of C3H4 will be left ? (Ideal gas law: PV = nRT, R= 0.082057 L atm/mole K)
%3D
%3D
Complete the following table and use it to help you answer the question.
->
3 CO2(g)
2 H20(g)
C3H4(g)
4 O2(g)
initial moles
change in moles
new moles
(expression)
new moles
(numerical value)
Transcribed Image Text:C3H4(g) + 4 O2(g) → 3 CO2(g) + 2 H2O(g) If 15.0 grams of C3H4(g) are placed in a 5.00L container at 350. K and allowed to react with CAcess O2(g) for 20 minutes, the partial pressure of CO2(g) is measured to be 4.50 atm. what mass of C3H4 will be left ? (Ideal gas law: PV = nRT, R= 0.082057 L atm/mole K) %3D %3D Complete the following table and use it to help you answer the question. -> 3 CO2(g) 2 H20(g) C3H4(g) 4 O2(g) initial moles change in moles new moles (expression) new moles (numerical value)
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