C3H₂ + NH/₂ + ³/20₁₂ → CzHz N + 3H₂ езне The feed to propylene ammoxidation proceso contains 10.0 mole to propylene 1200 ammonia, and 78.0% air. A fractional Conversion of 30.0% of the limiting reactant to achieved. Taking 100 mul of feed to as a bass, determine which reactant 15 limiting and the molar amounts of all gar constituents for a 305 conversion of the limiting reactanti determine the molar amounts in atomic species balancer and mollecalor specier balancen Goswers reactor 100 An 6.100 ml ₂10/21/ G120 my №₂/out Songomarinal て 02/0 0/0 air [ 6.74 ml N₂l molair Mesto (AN) (H₂) PWMS (Mul N₁13) har (nd Oc) MAL (MON₂) M²3513 N (M³) (3H₂N) Mund (Mathe) answers Desto² 7₂0mu) (3) 1x ning 2 q. U mul MM3 no₂² 1149 mul de AN 616 MINE nezn²N = 3.00 mil MHE 61.6 m) №₂ ₂02 9. Umul 11/₂0
C3H₂ + NH/₂ + ³/20₁₂ → CzHz N + 3H₂ езне The feed to propylene ammoxidation proceso contains 10.0 mole to propylene 1200 ammonia, and 78.0% air. A fractional Conversion of 30.0% of the limiting reactant to achieved. Taking 100 mul of feed to as a bass, determine which reactant 15 limiting and the molar amounts of all gar constituents for a 305 conversion of the limiting reactanti determine the molar amounts in atomic species balancer and mollecalor specier balancen Goswers reactor 100 An 6.100 ml ₂10/21/ G120 my №₂/out Songomarinal て 02/0 0/0 air [ 6.74 ml N₂l molair Mesto (AN) (H₂) PWMS (Mul N₁13) har (nd Oc) MAL (MON₂) M²3513 N (M³) (3H₂N) Mund (Mathe) answers Desto² 7₂0mu) (3) 1x ning 2 q. U mul MM3 no₂² 1149 mul de AN 616 MINE nezn²N = 3.00 mil MHE 61.6 m) №₂ ₂02 9. Umul 11/₂0
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
Related questions
Question
Use the atomic species balance for this chemical reaction. Do not use the extent of reaction or molecular species balances.
![## Propylene Ammoxidation Process
**Chemical Reaction:**
\[ \text{C}_3\text{H}_6 + \text{NH}_3 + \frac{3}{2} \text{O}_2 \rightarrow \text{C}_3\text{H}_3\text{N} + 3 \text{H}_2\text{O} \]
**Problem Statement:**
The feed to the propylene ammoxidation process contains 10.0% mole propylene, 12.0% ammonia, and 78.0% air. A fractional conversion of 30.0% of the limiting reactant is achieved. Taking 100 mol of feed as a basis, determine:
- The limiting reactant
- The molar amounts of all gas constituents for a 30% conversion of the limiting reactant
**Approach:**
- Determine the molar amounts in atomic species balance and molecular species balances.
**Diagram Explanation:**
- **Reactor Setup:**
- **Input (Feed Basis):**
- 100 mol of feed
- 10.0 mol C₃H₆/mol air
- 12.0 mol NH₃/mol air
- 78.0 mol O₂/mol air
- **Output:**
- Molar flow rates:
- \( n_{\text{C}_3\text{H}_6} \)
- \( n_{\text{NH}_3} \)
- \( n_{\text{O}_2} \)
- \( n_{\text{C}_3\text{H}_3\text{N}} \)
- \( n_{\text{H}_2\text{O}} \)
**Calculations:**
**Answers:**
- \( n_{\text{C}_3\text{H}_6} = 7.0 \text{ mol} \)
- \( n_{\text{NH}_3} = 9.0 \text{ mol} \)
- \( n_{\text{O}_2} = 11.6 \text{ mol} \)
- Unreacted flows to other species calculated
- Extent of reaction values at 30% conversion
- \( n_{\text{C}_3\text{H}_3\text{N}} = 3.0 \text{ mol} \)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9ba88ecd-654b-4f6b-9783-e93c33ca6a16%2Ffb412ddb-8c2d-4de9-89a7-4cc15480beb7%2Fdzqp4f_processed.jpeg&w=3840&q=75)
Transcribed Image Text:## Propylene Ammoxidation Process
**Chemical Reaction:**
\[ \text{C}_3\text{H}_6 + \text{NH}_3 + \frac{3}{2} \text{O}_2 \rightarrow \text{C}_3\text{H}_3\text{N} + 3 \text{H}_2\text{O} \]
**Problem Statement:**
The feed to the propylene ammoxidation process contains 10.0% mole propylene, 12.0% ammonia, and 78.0% air. A fractional conversion of 30.0% of the limiting reactant is achieved. Taking 100 mol of feed as a basis, determine:
- The limiting reactant
- The molar amounts of all gas constituents for a 30% conversion of the limiting reactant
**Approach:**
- Determine the molar amounts in atomic species balance and molecular species balances.
**Diagram Explanation:**
- **Reactor Setup:**
- **Input (Feed Basis):**
- 100 mol of feed
- 10.0 mol C₃H₆/mol air
- 12.0 mol NH₃/mol air
- 78.0 mol O₂/mol air
- **Output:**
- Molar flow rates:
- \( n_{\text{C}_3\text{H}_6} \)
- \( n_{\text{NH}_3} \)
- \( n_{\text{O}_2} \)
- \( n_{\text{C}_3\text{H}_3\text{N}} \)
- \( n_{\text{H}_2\text{O}} \)
**Calculations:**
**Answers:**
- \( n_{\text{C}_3\text{H}_6} = 7.0 \text{ mol} \)
- \( n_{\text{NH}_3} = 9.0 \text{ mol} \)
- \( n_{\text{O}_2} = 11.6 \text{ mol} \)
- Unreacted flows to other species calculated
- Extent of reaction values at 30% conversion
- \( n_{\text{C}_3\text{H}_3\text{N}} = 3.0 \text{ mol} \)
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