C1C1 C1C2 C2C2 D1D1 D1D2 D2D2 Sand 0.07 0.39 0.54 0.25 0.5 0.25 Land 0.18 0.49 0.33 0.06 0.22 0.72 If you sample an indiv who is C1C1D2D2, find the probabiltiy of him coming from the popualtation at sand.

C1C1 C1C2 C2C2 D1D1 D1D2 D2D2 Sand 0.07 0.39 0.54 0.25 0.5 0.25 Land 0.18 0.49 0.33 0.06 0.22 0.72 If you sample an indiv who is C1C1D2D2, find the probabiltiy of him coming from the popualtation at sand.

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

See similar textbooks

Similar questions

The number of successes and the sample size are given for a simple random sample from a population. Decide whether using the one-proportion z-interval procedure is appropriate. x= 13, n= 30 Not appropriate Appropriate
t13
A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 239.7-cm and a standard deviation of 0.8-cm. For shipment, 5 steel rods are bundled together.Find P58, which is the average length separating the smallest 58% bundles from the largest 42% bundles. P58 = -cmEnter your answer as a number accurate to 2 decimal place. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.
a A2 The sample of size n=87 Is drawn From a population whose standard deviation 189 Find The margin of ERROV for a 90%. Confieuence Interat
How do I do this? Please help
The average wait time to get seated at a popular restaurant in the city on a Friday night is 15 minutes. Is the mean wait time different for men who wear a tie? Wait times for 15 randomly selected men who were wearing a tie are shown below. Assume that the distribution of the population is normal. 13, 13, 14, 13, 17, 16, 17, 17, 13, 14, 15, 14, 16, 15, 14 What can be concluded at the the a = 0.10 level of significance level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: ?v Select an answer v H1: Select an answer v c. The test statistic ? v = (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is ? v a f. Based on this, we should Select an answer v the null hypothesis. g. Thus, the final conclusion is that ... O The data suggest the population mean is not significantly different from 15 at a = 0.10, so there is statistically insignificant…
Change in the average birth weight of babies born in the U.S. since 1990, in ounces 0 -0.5- -1.0 -1.5 1990 '95 ¹00 "Born between 37 and 41 and net including multiple births Source: Obstetrics and Gynecology prvy. 105 A local hospital wanted to see if the claim was true and randomly sampled 19 baby's weights and found an average weight of 7 pounds. Test the claim using a 10% level of significance that the mean weight significantly smaller than the national average of 7.5 pounds. Use the population standard deviation of 1.25 pounds. Give answer to at least 4 decimal places. What are the correct hypotheses? (Select the correct symbols.) pounds Ho: Select an answer♥ ?✔ H₁: Select an answer? Based on the hypotheses, find the following: Test Statistic = p-value = pounds The correct decision is to [Select an answer The correct summary would be: [Select an answer weight significantly smaller than the national average of 7.5 pounds. What is the type I error in this situation? Select an answer…
X ~ N(37.3, 5) a) What score is at the 73rd percentile? b) What score is at the 40th percentile?
unch Assume that the heights of women are normally distributed with a mean of 63.6 inches and a standard deviation of 2.5 inches. If 75 women are randomly selected, find the probability that they have a mean height between 63 and 65 inches. book O A. 0.2119 xt OB. 0.0188 O C. 0.9811 ccessible Resout O D. 0.3071 Tools for Success Multimedia Libral Skills for Success Purchase Options Details Study Plan Click to select your answer and then click Check Answer. Discussion IMG 8704.jpg Open file All parts showing Clear All Check Answer DOpen file Show all P Type here to search a 1:36 AM 4/16/2021 14 47
Hi how could you answer this question?
Due Sat 12/05/2020 11:59 pm A recent national report states the marital status distribution of the male population age 18 or older is as follows: Never Married (31.2%), Married (55.5%), Widowed (2.3%), Divorced (11%). The table below shows the results of a random sample of 1684 adult men from California. Test the claim that the distribution from California is as expected at the a = 0.01 significance level. a. Complete the table by filling in the expected frequencies. Round to the nearest whole number: Frequencies of Marital Status Outcome Frequency Expected Frequency Never Married 519 Married 941 Widowed 40 Divorced 184 b. What is the correct statistical test to use? Select an answer v c. What are the null and alternative hypotheses? Но: O Marital status and residency are independent. O Marital status and residency are dependent. O The distribution of marital status in California is not the same as it is nationally. O The distribution of marital status in California is the same as it…