(c). ty" +3ty' + y = 0, t>0; y₁(t) = t−1 Assume that y2 = v(t)y₁, using above approach with p(t) = 3/t, we have let u = = v' 1-10" + ( − 1 1/2 + 1/320² = 0 +2 x² + 1 = 0 -u u' t 1 1 -du = dt In |u| = − In|t|+C, u = ct-1 == – v = Y2 = udt = c₁ In |t| + c₂ © 1½ (c₁ In |t| + C2) t