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c. Find the value a for which P(x

c. Find the value a for which P(x

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Help with Part C please! This is not a test! This is a homework question that I’m stucked on.
Miraculin, a protein naturally produced in a rare tropical fruit, can convert a sour taste into a sweet taste; thus, it has the potential to be an alternative low-calorie sweetener. In Plant Science (May 2010), a group of Japanese environmental scientists investigated the ability of a hybrid tomato plant to produce miraculin. For a particular generation of the tomato plant, the amount x of miraculin produced (measured in micrograms per gram of fresh weight) had a mean of 105.3 and a standard deviation of 8.0. Assume that x is normally distributed. Complete parts a through c below. a. Find P(x> 117). P(x>117)= 0.0721 (Round to four decimal places as needed.) b. Find P(97<x< 112). P(97<x< 112) = 0.6503 (Round to four decimal places as needed.) c. Find the value a for which P(x <a) = 0.35. a = -0.38 (Round to two decimal places as needed.)
Transcribed Image Text:Miraculin, a protein naturally produced in a rare tropical fruit, can convert a sour taste into a sweet taste; thus, it has the potential to be an alternative low-calorie sweetener. In Plant Science (May 2010), a group of Japanese environmental scientists investigated the ability of a hybrid tomato plant to produce miraculin. For a particular generation of the tomato plant, the amount x of miraculin produced (measured in micrograms per gram of fresh weight) had a mean of 105.3 and a standard deviation of 8.0. Assume that x is normally distributed. Complete parts a through c below. a. Find P(x> 117). P(x>117)= 0.0721 (Round to four decimal places as needed.) b. Find P(97<x< 112). P(97<x< 112) = 0.6503 (Round to four decimal places as needed.) c. Find the value a for which P(x <a) = 0.35. a = -0.38 (Round to two decimal places as needed.)
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