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c. Encrypt the message WOLLONGONG with key = 3. d. Decrypt the ciphertext MQJJ with key = 3. %3D

c. Encrypt the message WOLLONGONG with key = 3. d. Decrypt the ciphertext MQJJ with key = 3. %3D

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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The following stream cipher operates on character A-Z one at a time. A character A-Z is mapped to Z26 = {0,1,2,.,25} in the usual way. For a key k e Z26, a key stream kıkzk3 .. is generated by the following rule: ki = k? +1 (mod 26), kin = k-1+n (mod 26). 'n-1 For a message m mim2...m,, where m; E Z26, the ciphertext c = c\C2...C, is calculated as follows Ci= m;+ k; (mod 26) c. Encrypt the message WOLLONGONG with key = 3. %3D d. Decrypt the ciphertext MQJJ with key = 3. %3D
Transcribed Image Text:The following stream cipher operates on character A-Z one at a time. A character A-Z is mapped to Z26 = {0,1,2,.,25} in the usual way. For a key k e Z26, a key stream kıkzk3 .. is generated by the following rule: ki = k? +1 (mod 26), kin = k-1+n (mod 26). 'n-1 For a message m mim2...m,, where m; E Z26, the ciphertext c = c\C2...C, is calculated as follows Ci= m;+ k; (mod 26) c. Encrypt the message WOLLONGONG with key = 3. %3D d. Decrypt the ciphertext MQJJ with key = 3. %3D
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