c. Derive the piston instantaneous acceleration as a function of the crank angle. • Piston Acceleration Speed dUp dUp d dt de @= de (a sin(0) [1- 1+ 2DD) 4² cos (0) √R²-sin²(
c. Derive the piston instantaneous acceleration as a function of the crank angle. • Piston Acceleration Speed dUp dUp d dt de @= de (a sin(0) [1- 1+ 2DD) 4² cos (0) √R²-sin²(
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Question
![c. Derive the piston instantaneous acceleration as a function of the crank angle.
. Piston Acceleration Speed
dUp dUp d
de
dt dᎾ
- (a sin(0) [1.
+
=
@=
cos(0)
√R²-sin²(
Son ² (1)D) w ²](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fac14b24d-6571-41c2-a7f0-ffb5d6f754d5%2Ff3ad3deb-86e0-4631-ba76-0ed6524e80dc%2Fpby1cy_processed.jpeg&w=3840&q=75)
Transcribed Image Text:c. Derive the piston instantaneous acceleration as a function of the crank angle.
. Piston Acceleration Speed
dUp dUp d
de
dt dᎾ
- (a sin(0) [1.
+
=
@=
cos(0)
√R²-sin²(
Son ² (1)D) w ²
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Step 1: Determine the given variables:
VIEWStep 2: Find the expression for the piston velocity with respect to the crank angle:
VIEWStep 3: Differentiate the expression with respect to θ:
VIEWStep 4: Differentiate sin(θ) and apply the chain rule to differentiate further:
VIEWStep 5: Simplify the expression:
VIEWStep 6: Combine like terms:
VIEWStep 7: Cancel out suitable terms from the numerator and denominator:
VIEWStep 8: Use the chain rule to differentiate the above expression with respect to time (t):
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