c. Charge on C₂ (in nC) = 18 Submit Answer Incorrect. Tries 4/10 Previous Tries d. Voltage across C₂ (in V) = Submit Answer Tries 0/10 e. Charge on C3 (in nC) =

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c. Charge on C₂ (in nC) =
Submit Answer Incorrect. Tries 4/10 Previous Tries
d. Voltage across C₂ (in V) =
Submit Answer Tries 0/10
e. Charge on C3 (in nC) =
Submit Answer Tries 0/10
f. Voltage across C3 (in V) =
Transcribed Image Text:c. Charge on C₂ (in nC) = Submit Answer Incorrect. Tries 4/10 Previous Tries d. Voltage across C₂ (in V) = Submit Answer Tries 0/10 e. Charge on C3 (in nC) = Submit Answer Tries 0/10 f. Voltage across C3 (in V) =
V
16 V
C₁
8 nF
C₂
10 nF
С3
1 nF
What are the charge on and the potential across each capacitor in the Figure?
Transcribed Image Text:V 16 V C₁ 8 nF C₂ 10 nF С3 1 nF What are the charge on and the potential across each capacitor in the Figure?
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“Since you have posted a question with multiple sub-parts, we will solve the first three sub-parts for you. To get the remaining sub-parts solved please repost the complete question and mention the sub-parts to be solved.”

 

Capacitance:

It is defined to be the ratio of the charge stored in the capacitor to the voltage applied across it. Mathematically,

C=QV                             (1)

where Q is the charge stored in the capacitor and V is the voltage applied across it.

 

Capacitance in Parallel circuits: 

When the capacitors C1, C2, . . ., and Cn are connected in parallel with each other, then their equivalent capacitance is given as

Ce=C1+C2+. . . +Cn

Capacitance in Series circuits: 

When the capacitors C1, C2, . . ., and Cn are connected in series, then their equivalent capacitance is given as

1Ce=1C1+1C2+. . . +1Cn

 

NOTE: 1 nF×1 V=1 nC

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