c) (X1, Y1, Z1) + (x2, Y2, z2) = (x1 + X2 + 3, yı + y2 + 3, z1 + z2 + 3) (сх, су, с2) с(х, у, 2) %3D O The set is a vector space. O The set is not a vector space because the additive identity property is not satisfied. The set is not a vector space because the additive inverse property is not satisfied. O The set is not a vector space because it is not closed under scalar multiplication. O The set is not a vector space because the distributive property is not satisfied. d) (X1, Y1, Z1) + (x2, Y2, z2) с (х, у, z) O The set is a vector space. (X1 + X2 + 7, Y1 + Y2 + 7, z1 + z2 + 7) (cx + 7c – 7, cy + 7c – 7, cz + 7c – 7) O The set is not a vector space because the additive identity property is not satisfied. O The set is not a vector space because it is not closed under scalar multiplication. O The set is not a vector space because the distributive property is not satisfied.
c) (X1, Y1, Z1) + (x2, Y2, z2) = (x1 + X2 + 3, yı + y2 + 3, z1 + z2 + 3) (сх, су, с2) с(х, у, 2) %3D O The set is a vector space. O The set is not a vector space because the additive identity property is not satisfied. The set is not a vector space because the additive inverse property is not satisfied. O The set is not a vector space because it is not closed under scalar multiplication. O The set is not a vector space because the distributive property is not satisfied. d) (X1, Y1, Z1) + (x2, Y2, z2) с (х, у, z) O The set is a vector space. (X1 + X2 + 7, Y1 + Y2 + 7, z1 + z2 + 7) (cx + 7c – 7, cy + 7c – 7, cz + 7c – 7) O The set is not a vector space because the additive identity property is not satisfied. O The set is not a vector space because it is not closed under scalar multiplication. O The set is not a vector space because the distributive property is not satisfied.
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter8: Applications Of Trigonometry
Section8.3: Vectors
Problem 14E
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