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C++ Why does a superimposed assignment operator return a reference to the assigned object? See below. Foo & operator = (const Foo & rhs) {              // magic               return this; } }   Select one or more options: 1. In order for the operator to be able to chain. 2. To set all assigned member variables to the object left. 3. Because a superimposed allocation operator must always return just that: a reference to itself. 4. For the assignment (in effect copying) to be deep instead of superficial. 5. To avoid this becoming a dangling pointer. 6. None of the above.

C++ Why does a superimposed assignment operator return a reference to the assigned object? See below. Foo & operator = (const Foo & rhs) {              // magic               return this; } }   Select one or more options: 1. In order for the operator to be able to chain. 2. To set all assigned member variables to the object left. 3. Because a superimposed allocation operator must always return just that: a reference to itself. 4. For the assignment (in effect copying) to be deep instead of superficial. 5. To avoid this becoming a dangling pointer. 6. None of the above.

Database System Concepts
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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C++

Why does a superimposed assignment operator return a reference to the assigned object? See below.

Foo & operator = (const Foo & rhs) {

             // magic

              return this; }

}

 

Select one or more options:

1. In order for the operator to be able to chain.

2. To set all assigned member variables to the object left.

3. Because a superimposed allocation operator must always return just that: a reference to itself.

4. For the assignment (in effect copying) to be deep instead of superficial.

5. To avoid this becoming a dangling pointer.

6. None of the above.

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