(c) What is the probability that a random sample of 19 pregnancies has a mean gestation period of 215 days or less? Notice that the probability in this case is for the mean of a sample of the population. This means that the sampling distribution of the mean should be used and not the population distribution. In part (b). µ was calculated to be 222 and was calculated to be 4.358899. Therefore, the sampling distribution of x for a sample size of 19 is approximately normal with a mean μ- = 222 and standard deviation o-=4.358899. While either technology or a standard normal distribution table could be used to calculate the desired probability, in thi problem, use technology.
(c) What is the probability that a random sample of 19 pregnancies has a mean gestation period of 215 days or less? Notice that the probability in this case is for the mean of a sample of the population. This means that the sampling distribution of the mean should be used and not the population distribution. In part (b). µ was calculated to be 222 and was calculated to be 4.358899. Therefore, the sampling distribution of x for a sample size of 19 is approximately normal with a mean μ- = 222 and standard deviation o-=4.358899. While either technology or a standard normal distribution table could be used to calculate the desired probability, in thi problem, use technology.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Standard Dev is 19
Question is asking me to use technology to find the answer to this problem. Can you explain how to do this such as with either the Graphing calculator and Excel?

Transcribed Image Text:(c) What is the probability that a random sample of 19 pregnancies has a mean gestation period of 215 days or less?
Notice that the probability in this case is for the mean of a sample of the population. This means that the sampling distribution of the mean should be used and not the population distribution.
In part (b), the sample mean (\( \mu_{\bar{x}} \)) was calculated to be 222 and the standard deviation (\( \sigma_{\bar{x}} \)) was calculated to be 4.358899. Therefore, the sampling distribution of \( \bar{x} \) for a sample size of 19 is approximately normal with a mean \( \mu_{\bar{x}} = 222 \) and a standard deviation \( \sigma_{\bar{x}} = 4.358899 \). While either technology or a standard normal distribution table could be used to calculate the desired probability, in this problem, use technology.
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