(c) Use part (b) to show |f(2)| zn+1 Ar + B on Yr pn+1 (d) Use part (b) and the Basic Integral Bound to show 1 |cn| = 2ni f(2) dz zn+1 Ar + B sn (e) Now take a limit as r → o to show c, = 0 for n> 2. Why doesn't this work for n = 1? %3D
(c) Use part (b) to show |f(2)| zn+1 Ar + B on Yr pn+1 (d) Use part (b) and the Basic Integral Bound to show 1 |cn| = 2ni f(2) dz zn+1 Ar + B sn (e) Now take a limit as r → o to show c, = 0 for n> 2. Why doesn't this work for n = 1? %3D
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
100%

Transcribed Image Text:Basic Integral Bound
ASSUMPTION FOR PART b
Let f(2) be continuous along the curve y and have |f(z)| < M along y.
Let f(z) be an entire function that satisfies
(Inequality 1)
(-) d: < M Length().
Then
Iftz)| SA+ B|z| for some positive constants.
Then f(2) is a linear function f(2) = c, + C,z for some complex constants
QUESTION
Prove this as follows. As f(2) is entire, it has
a series expansion about z = 0
-Σ
f(2) = co + c1z + c22² + c22³ + •
n=0
To prove the result we just need to prove
Cn = 0 for all n > 2
for then the series expansion will reduce to just f(z) = co+cız. Because
f(2) is entire its radius of convergence is infinite and therefore we have
that the coefficients in the series are given by
1
f(2)
Cn
dz
2ni
|z|=r
and this holds for any r > 0. To make this look a little more like some
of the notation above let
Tr = the circle of radius r defined by |z| =r
and then our formula for c, becomes
Cn
dz
2πί
(a) What is Length(,)?
(b) Use the assumption of inequality 1 to show
|f(2)| < Ar + B
on Yr

Transcribed Image Text:(c) Use part (b) to show
f(z)
Ar + B
on Yr
zn+1
pn+1
(d) Use part (b) and the Basic Integral Bound to show
f(2)
dz <
zn+1
Ar + B
|cn|
2ni
(e) Now take a limit as r → o to show cn
0 for n > 2. Why doesn't
this work for n = 1?
Expert Solution

This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 2 steps

Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, advanced-math and related others by exploring similar questions and additional content below.Recommended textbooks for you

Advanced Engineering Mathematics
Advanced Math
ISBN:
9780470458365
Author:
Erwin Kreyszig
Publisher:
Wiley, John & Sons, Incorporated

Numerical Methods for Engineers
Advanced Math
ISBN:
9780073397924
Author:
Steven C. Chapra Dr., Raymond P. Canale
Publisher:
McGraw-Hill Education

Introductory Mathematics for Engineering Applicat…
Advanced Math
ISBN:
9781118141809
Author:
Nathan Klingbeil
Publisher:
WILEY

Advanced Engineering Mathematics
Advanced Math
ISBN:
9780470458365
Author:
Erwin Kreyszig
Publisher:
Wiley, John & Sons, Incorporated

Numerical Methods for Engineers
Advanced Math
ISBN:
9780073397924
Author:
Steven C. Chapra Dr., Raymond P. Canale
Publisher:
McGraw-Hill Education

Introductory Mathematics for Engineering Applicat…
Advanced Math
ISBN:
9781118141809
Author:
Nathan Klingbeil
Publisher:
WILEY

Mathematics For Machine Technology
Advanced Math
ISBN:
9781337798310
Author:
Peterson, John.
Publisher:
Cengage Learning,

