C {t e2t sin t} = = 25 (s²+1)² [(0-2)2+1] = (B) (E) 8-2 [(8-2)²+1]² 2(8-2) [(8-2)²+1]² 2(8-2) (C) -2)2+1
C {t e2t sin t} = = 25 (s²+1)² [(0-2)2+1] = (B) (E) 8-2 [(8-2)²+1]² 2(8-2) [(8-2)²+1]² 2(8-2) (C) -2)2+1
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter11: Differential Equations
Section11.CR: Chapter 11 Review
Problem 16CR
Related questions
Question
solve question 3 please differential equations
![Q2) An integrating factor of
(A) e-*
(B) e
(C) e-
Q3) L {tet sint} =
(A) (²+1)²
(D)
2
[(8-2)²+1]
(B)
(E)
(x²+e)dx + (e" + 2ye)dy = 0 is
(D) e
(E) e-2
8-2
[(8-2)²+1]²
2(8-2)
[(6-2)2+1)
2(8-2)
(C) (-2)²+1
||
m² ey du = 0.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F232632b1-f2d3-4d97-a5a4-d15def76356a%2Fc29d8ced-8e46-4a7e-980e-756dae277105%2Fou9ur8o_processed.png&w=3840&q=75)
Transcribed Image Text:Q2) An integrating factor of
(A) e-*
(B) e
(C) e-
Q3) L {tet sint} =
(A) (²+1)²
(D)
2
[(8-2)²+1]
(B)
(E)
(x²+e)dx + (e" + 2ye)dy = 0 is
(D) e
(E) e-2
8-2
[(8-2)²+1]²
2(8-2)
[(6-2)2+1)
2(8-2)
(C) (-2)²+1
||
m² ey du = 0.
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