c) Show that the vector field W(x, y, z) = (2yz+ xz – x², –2xz – yz + y?, y² – x² + z²) - - is a vector potential for V.
c) Show that the vector field W(x, y, z) = (2yz+ xz – x², –2xz – yz + y?, y² – x² + z²) - - is a vector potential for V.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
Only part C
![Consider in (x, y, z) space the vector field V(x, y,z) = (2x + 3y, 2y + 3x, –4z) and the
function
F(x,у, 2) — а - х* +b.y? +c:2?+d х-у, (х,у, 2) € R'.
- с.
= a ·
a) Find constants a, b,c and d so that V = VF.
b) Compute the tangential line integral of V along the right half of the unit circle in
the (y,z) plane centered at (0,1,1) with an orientation of
your
choice.
c) Show that the vector field
W(x, y, z) = (2yz + xz – x², –2xz – yz + y?, y² – x² + z²)
is a vector potential for V.
d) An open surface F is given by F =
{(x, y, z) | z = 4 – x² – y? , z > 0} .
Compute the flux of V through F after choosing orientations of F and its boun-
dary curve ƏF that fulfil the right-hand rule.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F16d5ab89-cae5-4d80-b8cc-2688a1c981a8%2F0970b2e7-b14d-4c25-89f1-a9271b03c762%2Fhbfwy83_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Consider in (x, y, z) space the vector field V(x, y,z) = (2x + 3y, 2y + 3x, –4z) and the
function
F(x,у, 2) — а - х* +b.y? +c:2?+d х-у, (х,у, 2) € R'.
- с.
= a ·
a) Find constants a, b,c and d so that V = VF.
b) Compute the tangential line integral of V along the right half of the unit circle in
the (y,z) plane centered at (0,1,1) with an orientation of
your
choice.
c) Show that the vector field
W(x, y, z) = (2yz + xz – x², –2xz – yz + y?, y² – x² + z²)
is a vector potential for V.
d) An open surface F is given by F =
{(x, y, z) | z = 4 – x² – y? , z > 0} .
Compute the flux of V through F after choosing orientations of F and its boun-
dary curve ƏF that fulfil the right-hand rule.
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