(c) Show Force on a negative charge BO O q<0€
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- (a) Two thin hollow plastic spheres, about the size of a ping-pong ball with masses (m1 = m2 = 2e-3 kg) have been rubbed with wool. Sphere 1 has a charge q1 = -8e-9 C and is at location Forav on 92 m. Sphere 2 has a charge q2 = -3e-9 C and is at location m. It will be useful to draw a diagram of the situation, including the relevant vectors. What is the relative position vector pointing from q1 to q2? m What is the distance between q1 and q2? F = What is the unit vector i in the direction of ?? What is the magnitude of the gravitational force exerted on 9, by q1? ´grav on q, What is the gravitational force (vector) exerted on q2 by q1? 1 9192 What is the value of 47€0 |F|2, What is the electric force (vector) exerted on q2 by q1? Felectric on q2 = NA point charge q = 1 nC is placed at the following position in the x-yplane: at (x, y) = (0, 3m). Calculate the magnitude of the electric field atthe point P: (x, y) = (0, 0).O +Q A L +Q B moyectro ☺ (a) Determine the electric field, E, at the origin due to the two point charges at A and B. (b) Repeat but let the charge at B be reversed in sign. potear bu?
- (b)Consider two charges of charge -3e-09 C nailed in place on the y-axis straddling the origin (one charge 0.006 m above the origin and one charge 0.006 m below the origin). A proton is at the origin and it is launched directly to the right (along the x-axis). i.What is the escape speed (in m/s) of the proton (middle charge)? (Again, assume the two outer charges are fixed in place) a)1.14e+06 b)4.28e+06 c)5.12e+05 d)1.97e+06 e)1.31e+06 f)2.77e+06 ii.If the proton (middle charge) is launch with half of the escape speed, how far away (in m) from its starting point will it stop and turn around? a)0.00794 b)0.00460 c)0.0112 d)0.0173 e)0.00529 f)0.00206 Please answer both parts kindly, i will highly appreciate it!(c) Calculate the electric field, E, at the origin for the three scenarios given. The magnitude 4760 of all charges is 3 C and the charges form squares with each side 1-m long. k = 8.99 x 10°Nm²/C². =Asap