C₁: r₁(s) C₂: r₂(t) C3 r3(u) = = = (s 2)i+ (2s² - 1)j + k 2t² i + (3t+7)j + (t+1) k (SER) (t = R) (u²+ 4u + 3)i + (u² + 6)j + (u + 2) k (u € R)

Q: Find curl (5z i + 6x j + 9y k). curl(5z i + 6x j + 9y k) = ( i )i + ( i )j + ( i )k

A: Given: To obtain the curl (5z i+6x j+9y k)That is to find: ∇×Fwhere here F=5z i+6x j+9y k

Q: Find curl (3z i + 4x j + 9y k). curl (3z i + 4x j + 9y k) = ( i )i + ( i

A:

Q: Find curl (6z i + 7x j + 8y k). curl(6z i + 7x j + 8y k) = ( i )i + ( i )j + ( i )k

A:

Q: Find curl (5z i + 6x j + 3y k). curl (5z i + 6x j + 3y k) = ( i )i + ( i i )k

A:

Q: Find curl (2z i + 3x j + 5y k). curl (2z i + 3x j + 5y k) (i )i + ( i j+ ( i )k

A:

Q: (r2+2rt-4t2)dr-(r2-8rt-4t2)dt=0

A:

Q: Lt² V4-t² dt V(4-x)/(2\x) x(4-x)

A:

Q: Find curl (5z i + 6x j + 2y k). curl (5z i + 6x j+ 2y k) = ( i )i + ( i )j + ( i )k Save for Later

A:

Q: Cakulate (3i+2j+k) • (i + zj - k

A:

Q: 3y +5 (5y-7)2 dy

A: We can find the integration as below.

Q: Find curl (8z i + 9x j + 8y k). curl (8z i + 9x j + 8y k) = ( i )i + ( i )j + ( i )k

A: We know: Where P, Q and R correspond to the components of a given vector field:F→=Pi→+Qj→+Rk→ curl…

Q: -x + y -z = −17 2xy + z = 3x + 2y + z = (x, y, z) =

A: -x+y-z=-17......(1)2x-y+z=24......(2)3x+2y+z=16......(3)

Q: Find curl (4z i + 5x j+ 2y k).

A:

Q: Solve (ut)² + (Ux)² = 1

A: