C R₁ Vin www HH For the active high-pass filter above, calculate the break frequency in Hz and the high-frequency gain in dB if R₁ = 33 k2, R₂ = 820 ks and C = 3.3 nF. fB = 3.386 kHz G = 27.91 dB fB = 3.289 kHz G = 5.04 dB fB 6.046 kHz G = 5.04 dB fB = 1.461 kHz Vout G = 27.91 dB

C R₁ Vin www HH For the active high-pass filter above, calculate the break frequency in Hz and the high-frequency gain in dB if R₁ = 33 k2, R₂ = 820 ks and C = 3.3 nF. fB = 3.386 kHz G = 27.91 dB fB = 3.289 kHz G = 5.04 dB fB 6.046 kHz G = 5.04 dB fB = 1.461 kHz Vout G = 27.91 dB

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Concept explainers

Filter

A filter is a device or process which removes some of the unwanted features or components like frequencies from a signal in signal processing. The feature of filters is the complete or partial suppression of some part of the signal, and filtering is a class of signal processing. This most often means removing some frequency bands or some frequencies. In the frequency domain, the filters do not exclusively act, especially in the image processing field many other targets for filtering exist. Without having to act in the frequency domain, the correlations can be removed for certain frequency components and not for others. The filters are widely used in electronics and telecommunication, in television, radio, radar, audio recording, music synthesis, control systems, computer graphics, and image processing.

Question

R₁
Vin W
C
HH
G = 27.91 dB
fB = 3.289 kHz
For the active high-pass filter above,
calculate the break frequency in Hz and
the high-frequency gain in dB if R₁
=
33
kQ2, R₂ = 820 k and C = 3.3 nF.
fB = 3.386 kHz
G = 5.04 dB
fB = 6.046 kHz
G = 5.04 dB
fB = 1.461 kHz
K2
G = 27.91 dB
Vout

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