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(C PROGRAMMING ONLY) 1. Leap Year Detector by CodeChum Admin Let’s try to find out whether a year has 365 or 366 days. To do this, we need to create a leap year detector!   Conditions for a leap year: 1.) year must be divisible by 4 and not divisible by 100 2.) If year is divisible by 100, it must be divisible by 400 for it to be a leap year.   Instructions: You are provided with the isLeapYear() function which is already declared and defined for you. Your task is to ask the user for a year and then call the isLeapYear function to check whether the year is a leap year or not. Input 1. Year to be checked Output If a certain year is a leap year, print " is a leap year" Otherwise, print " is not a leap year" Enter year: 2020 2020 is a leap year

(C PROGRAMMING ONLY) 1. Leap Year Detector by CodeChum Admin Let’s try to find out whether a year has 365 or 366 days. To do this, we need to create a leap year detector!   Conditions for a leap year: 1.) year must be divisible by 4 and not divisible by 100 2.) If year is divisible by 100, it must be divisible by 400 for it to be a leap year.   Instructions: You are provided with the isLeapYear() function which is already declared and defined for you. Your task is to ask the user for a year and then call the isLeapYear function to check whether the year is a leap year or not. Input 1. Year to be checked Output If a certain year is a leap year, print " is a leap year" Otherwise, print " is not a leap year" Enter year: 2020 2020 is a leap year

Database System Concepts
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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(C PROGRAMMING ONLY)

1. Leap Year Detector
by CodeChum Admin

Let’s try to find out whether a year has 365 or 366 days. To do this, we need to create a leap year detector!

 

Conditions for a leap year:

1.) year must be divisible by 4 and not divisible by 100

2.) If year is divisible by 100, it must be divisible by 400 for it to be a leap year.

 

Instructions:

You are provided with the isLeapYear() function which is already declared and defined for you.
Your task is to ask the user for a year and then call the isLeapYear function to check whether the year is a leap year or not.
Input

1. Year to be checked

Output

If a certain year is a leap year, print "<INSERT_YEAR_HERE> is a leap year"
Otherwise, print "<INSERT_YEAR_HERE> is not a leap year"

Enter year: 2020
2020 is a leap year

Input main.c + c 1. Year to be checked 1 #include<stdio.h> int isleapYear(int); Output int main(void) { // TODO: Write your code here If a certain year is a leap year, print <INSERT_YEAR_HERE> is a leap year" Otherwise, print " return 0; <INSERT_YEAR_HERE> is not a leap 9 } year" 10 11 - int isleapYear(int n) { if( (n % 4 (n % 100 ) { return 1; } 0 && n % 100 != 0) || 0 && n % 400 Enter year: 2020 13 2020 is a leap year 14 15 - 16 17 18 19 return 0; 1234 567090123456789 H H 1 111 111 H
Transcribed Image Text:Input main.c + c 1. Year to be checked 1 #include<stdio.h> int isleapYear(int); Output int main(void) { // TODO: Write your code here If a certain year is a leap year, print <INSERT_YEAR_HERE> is a leap year" Otherwise, print " return 0; <INSERT_YEAR_HERE> is not a leap 9 } year" 10 11 - int isleapYear(int n) { if( (n % 4 (n % 100 ) { return 1; } 0 && n % 100 != 0) || 0 && n % 400 Enter year: 2020 13 2020 is a leap year 14 15 - 16 17 18 19 return 0; 1234 567090123456789 H H 1 111 111 H
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