C programming language  solve the answer according to the values ​​I gave student no : 2012010206083

Computer Networking: A Top-Down Approach (7th Edition)
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Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
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C programming language 

solve the answer according to the values ​​I gave student no : 2012010206083

Assume for the program given below that the elements of array A are your student number.
Assume that Data type of int is stored in 1 byte (8 bits) in memory. According to this
information, write the output of the program given below.
Note: Use the given assumption to get the output, don't run the code in the computer you will
get wrong output.
Örnek Hesaplama (Sample Calculation):
öğrenci No (Student No)
A Dizisi (Array A)
{1,8,1,0,2,0,6,0,3,7}
{2,0,1,5,0,1,0,2,0,6,0,4,7}
1810206037
2015010206047
#include <atdio.h>
#include <stdlib.h>
int main () {
int A[13] ={ your student number};
unsigned int s1=0, s2=0;
for (int i-0; i<13; i++)
{
if (A[1] 2==0)
s1= si+A[i] ;
else
s2= s2+A[i] ;
printf ("Output 1 : *y \n", s1);
printf ("Output 2 : *y \n", s2);
s1=s1>>1;
s2=s2<<2;
: *u \n", s1):
printf ("after si>>1 Out put 3
printf ("after s2<<2 Output 4: %u \n", s2);
printf ("a1ls2 Output 5: *u \n", s1 |s2);
printf ("s1^32 Output 6: *u \n", s1^s2);
printf ("316s2 Output 7: %u \n", si &s2);
getchar ();
return 0;
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Transcribed Image Text:Assume for the program given below that the elements of array A are your student number. Assume that Data type of int is stored in 1 byte (8 bits) in memory. According to this information, write the output of the program given below. Note: Use the given assumption to get the output, don't run the code in the computer you will get wrong output. Örnek Hesaplama (Sample Calculation): öğrenci No (Student No) A Dizisi (Array A) {1,8,1,0,2,0,6,0,3,7} {2,0,1,5,0,1,0,2,0,6,0,4,7} 1810206037 2015010206047 #include <atdio.h> #include <stdlib.h> int main () { int A[13] ={ your student number}; unsigned int s1=0, s2=0; for (int i-0; i<13; i++) { if (A[1] 2==0) s1= si+A[i] ; else s2= s2+A[i] ; printf ("Output 1 : *y \n", s1); printf ("Output 2 : *y \n", s2); s1=s1>>1; s2=s2<<2; : *u \n", s1): printf ("after si>>1 Out put 3 printf ("after s2<<2 Output 4: %u \n", s2); printf ("a1ls2 Output 5: *u \n", s1 |s2); printf ("s1^32 Output 6: *u \n", s1^s2); printf ("316s2 Output 7: %u \n", si &s2); getchar (); return 0; Window More questions next page Page ? of 5
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